A²-b²=(a-b)(a+b)
4x² - 25= (2x)²- 5² =(2x-5)(2x+5)
You do not have this choice, so the answer is D.None of the above.
Answer:
45.1feet
Step-by-step explanation:
Given the following
∠I=90°
∠G=62°, and
GH = 96 feet = Hypotenuse
Required
IG = Adjacent side
Using the SOH CAH TOA identity
Cos theta = Adj/hyp
Cos 62 =IG/96
IG = 96cos62
IG = 96(0.4695)
IG = 45.1feet
Hence the length of IG to the nearest tenth is 45.1feet
Area of Triangle:
A = 1/2 bh = 1/2 (5)(12) = 30 m^2
Area of semicircle:
A = 1/2 π r^2 = 1/2 π 6^2 = 18<span>π m^2
Area of figure = </span>Area of semicircle + Area of Triangle
Area of figure = 18π + 30 m^2
Answer is C.
18π + 30 m^2
11.45
the 11 is ur whole number...it stays ur whole number
the 0.45 is ur fraction...and since the last number (5) is in the hundredths place, put it over 100
so u now have : 11 45/100 which reduces to 11 9/20 and if u need it in improper fraction form, it is 229/20
