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3 years ago

Which function can be used to describe the sequence? -2/3, -4, -24

Mathematics

1 answer:

pychu [463]3 years ago

5 0

Answer #3 is correct

6 is the common ratio (r)
first term is -2/3 (a)
the general equation is f(x)=a(r)^x-1
so plug in the number
f(x)=-2/3(6)^x-1

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How do you write 9.88 ×10 square in standard form

KIM [24]

U right 9.88•10 in standard form like 98800000000.

8 0

2 years ago

Can someone please help??

Vsevolod [243]

Answer:

let the number of cows = x

let the number of chickens = y

since there are 42 heads:

x + y = 42

and since a cow has 4 legs, and a chicken has 2

4x + 2y = 144

from first equation:

x + y = 42

x = 42 - y (now, we will substitute this in the second equation)

4(42 - y) + 2y = 144

168 - 4y + 2y = 144

2y = 168 - 144

2y = 24

y = 12

now, we know the number of chickens. we will replace y with 12 in the first equation since it is more simpler

x + 12 = 42

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So, there are 30 cows and 12 chickens

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2 years ago

If r=1 and 0=5pie/3, what is the approximate arc length?

Masja [62]

Answer:

5.236 units

Step-by-step explanation:

The relation between r, θ and arc length ( l ) is,

l = rθ

l = 1 * 5π / 3

( The value of π = 3.14 approximately )

5π = 5 x 3.14 = 15.7

l = 1 * 5π / 3

= 5π / 3

= 15.7/3

l = 5.236 units

Note : -

Arc length is denoted by " l ".

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2 years ago

In ⊙H, Arc I K ≅ Arc J K, mArc I K = (11x + 2)°, and mArc J K = (12x – 7)°.

Bumek [7]

Answer:

202

Step-by-step explanation:

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7 0

2 years ago

Read 2 more answers

A spherical ball just fits inside a cylindrical can,16 centimeters y'all, with a diameter of 16 centimeters. What is the express

Veseljchak [2.6K]

Answer:

The correct answer is the expression of the volume of the sphere is $\frac{4}{3}$ ×π× $8^{3}$ and the expression of the volume of the leftover space is π× $8^{3}$ ×16 - $\frac{4}{3}$ ×π× $8^{3}$ .

Step-by-step explanation:

Height of the given cylindrical can = 16 cms.

Diameter of the given cylindrical can = 16 cms.

Now a spherical ball just fits in this given cylindrical can. Thus the diameter of the ball is equal to the diameter of the can, equal to 16 cms.

Thus the expression of the volume of ball = $\frac{4}{3}$ ×π× $r^{3}$ = $\frac{4}{3}$ ×π× $8^{3}$

Expression of the volume of the cylindrical can is π× $r^{3}$ × h = π× $8^{3}$ ×16

Expression of the leftover volume would be volume of can minus volume of the ball = π× $8^{3}$ ×16 - $\frac{4}{3}$ ×π× $8^{3}$ .

7 0

2 years ago