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Nitella [24]
2 years ago
12

Can you guys pls help

Mathematics
1 answer:
miskamm [114]2 years ago
8 0

Check the picture below.

so the lateral area of the pyramid is really just the area of four triangles whose base is 10 and height is also 10, now, we're excluding the bottom because that's not lateral area.

\stackrel{\textit{area of four triangles}}{4\left[\cfrac{1}{2}(\stackrel{b}{10})(\stackrel{h}{10}) \right]}\implies 2(100)\implies \text{\LARGE 200}~ft^2

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YA is the angle bisector of ZXYZ. If mZXYZ = 52°, what is mZZYA?
antoniya [11.8K]

Given:

YA is the angle bisector of \angle XYZ.

m\angle XYZ=52^\circ

To find:

The measure of m\angle ZYA.

Solution:

It is given that YA is the angle bisector of \angle XYZ. It means

m\angle XYA=m\angle ZYA            ...(i)

Now,

m\angle XYA+m\angle ZYA=m\angle XYZ

m\angle ZYA+m\angle ZYA=52^\circ            [Using (i)]

2m\angle ZYA=52^\circ

Divide both sides by 2.

m\angle ZYA=\dfrac{52^\circ}{2}

m\angle ZYA=26^\circ

Therefore, the required value is m\angle ZYA=26^\circ.

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Answer:

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