OK, let's try with no figure. We have an isosceles triangle sides s,s, and b.
Opposite b is angle t.
Draw the altitude h to bisect t. We have two right triangles, legs b/2 and h, hypotenuse s. The angle opposite b/2 is t/2 so
sin(t/2) = (b/2)/s = b/2s
So we arrived at the first part,
b = 2s sin(t/2)
The area of a triangle with sides s,s and included angle t is
A = (1/2) s² sin t
Hello Shaffer23,
All sides of a square are the same length so since the side is 10 units
Perimeter=40units
but to find the area of a square it is BasexHeight
10x10
Area is 100
So the answer would be the units for area
~Naterator
Please Thank and Rate If This Is Helpful <3
Step-by-step explanation:
In triangle,
<u> XYZ</u> <u>PYZ</u>
XZ = PZ = 12cm
XY = PY = 5cm
YZ = YZ (Common side)
<em><u>Hence</u></em><em><u>,</u></em>
As three sides of the two triangles are equal so,
<em><u>Triangle XYZ is congruent to Triangle PYZ by SAS congruence condition </u></em>