Tami thought that the perimiter is length plus width, which gave her 100. The actual width is 20
<h3 /><h3>▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄</h3><h3>Required Solution :</h3>
Let the first even number be 'x' & the second even number be (x + 2)
<u>According to the Question</u>,
⇒x + (x + 2) = 34
⇒x + x + 2 = 34
⇒2x + 2 = 34
⇒2x = 34 - 2
⇒2x = 32
⇒x = 32/2
⇒x = 16
⇒First even number = x = 16
⇒Second even number = (x + 2) = 16 + 2 = 18
<u>∴</u><u> </u><u>The t</u><u>wo consecutive even n</u><u>u</u><u>m</u><u>b</u><u>e</u><u>r</u><u>s</u><u> are 16 & 18</u> ...!
<h3>Verefication : </h3>
As, In our Question it was given that "The sum of two consecutive even numbers is thirty-four". So, as we got our two consecutive even numbers as 16 & 18 ... By this, we can say that these both even numbers should be equals to 34, i.e., 16 + 18 = 34. Hence, The equation which we formed is correct ...!
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Answer:
<h3>40 degrees</h3>
Step-by-step explanation:
If the temperature dropped 5 degrees every hour, this can be expressed as;
5 degree = 1 hour
To get the total number of degree dropped fro 8hours, we will say;
x degree = 8hours where x is the temperature drop in all
Solving both equality
5 degree = 1 hour
x degree = 8 hours
cross multiply
x * 1 = 5 * 8
x = 40 degrees
<em>Hence the total temperature drop in all is 40°</em>
<span>B(n) = A(1 + i)^n - (P/i)[(1 + i)^n - 1]
where B is the balance after n payments are made, i is the monthly interest rate, P is the monthly payment and A is the initial amount of loan.
We require B(n) = 0...i.e. balance of 0 after n months.
so, 0 = A(1 + i)^n - (P/i)[(1 + i)^n - 1]
Then, with some algebraic juggling we get:
n = -[log(1 - (Ai/P)]/log(1 + i)
Now, payment is at the beginning of the month, so A = $754.43 - $150 => $604.43
Also, i = (13.6/100)/12 => 0.136/12 per month
i.e. n = -[log(1 - (604.43)(0.136/12)/150)]/log(1 + 0.136/12)
so, n = 4.15 months...i.e. 4 payments + remainder
b) Now we have A = $754.43 - $300 = $454.43 so,
n = -[log(1 - (454.43)(0.136/12)/300)]/log(1 + 0.136/12)
so, n = 1.54 months...i.e. 1 payment + remainder
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