What are the zero(s) of f(x + 3)?

Mathematics

1 answer:

Pavlova-9 [17]3 years ago

4 0

Answer:

function f(x) = x + 3 has a zero at x = 3 since f(3) = 0.

Step-by-step explanation:

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Please solve the problem

jek_recluse [69]

Treat the matrices on the right side of each equation like you would a constant.

Let 2X + Y = A and 3X - 4Y = B.

Then you can eliminate Y by taking the sum

4A + B = 4 (2X + Y) + (3X - 4Y) = 11X

==> X = (4A + B)/11

Similarly, you can eliminate X by using

-3A + 2B = -3 (2X + Y) + 2 (3X - 4Y) = -11Y

==> Y = (3A - 2B)/11

It follows that

$X=\dfrac4{11}\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\dfrac1{11}\begin{bmatrix}7&-10\\-7&11\end{bmatrix} \\\\ X=\dfrac1{11}\left(4\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\left(\begin{bmatrix}48&-12\\40&88\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\begin{bmatrix}55&-22\\33&99\end{bmatrix} \\\\ X=\begin{bmatrix}5&-2\\3&9\end{bmatrix}$

Similarly, you would find

$Y=\begin{bmatrix}2&1\\4&4\end{bmatrix}$

You can solve the second system in the same fashion. You would end up with

$P=\begin{bmatrix}2&-3\\0&1\end{bmatrix} \text{ and } Q=\begin{bmatrix}1&2\\3&-1\end{bmatrix}$

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A. Tomás collects sports cards. The number of baseball

sleet_krkn [62]

• 18 baseball cards
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The only relationships shown in the table is in week 1, where the ratio of baseball to football cards is baseball : football = 9:6
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3 years ago

A gift box is 8 inches long, 3inches wide, and 4inches tall. What is the approximate length of its longest diagonal?A? 9.4inches

Doss [256]

Given parameters:

Length of the gift box = 8 inches

Width of the box = 3 inches

Height of the box = 4 inches

Unknown :

Length of its longest diagonal = ?

Solution:

This is a rectangular box.