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2 years ago

If X + Y = 212 and xy = 27 find the value of (x³+y³)

1 answer:

lisabon 2012 [21]2 years ago

4 0

X^3 + y^3 = (x + y)(x^2 - xy +’y^2)
X^2 + y^2 = (x+y)^2 - 2xy
So
X3 +y^3 = 212((212^2-2(27)-27))
= 212(46983)
= 9,960,396

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If X + Y = 212 and xy = 27 find the value of (x³+y³)​

If X + Y = 212 and xy = 27 find the value of (x³+y³)