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Licemer1 [7]
3 years ago
10

Two rectangles have the same width. One is 12 units long and the other is 8 units long. The area of the first rectangle is 320 s

quare units more than the area of the second rectangle. Find the width of each rectangle.
Mathematics
1 answer:
Paraphin [41]3 years ago
5 0

Answer:

80

Step-by-step explanation:

let w = the width of the rectangles

then

12w = the area of one rectangle

8w = the area of other

:

12w - 8w = 320

4w = 320

w = 320/4

w = 80 units wide

;

:

Check

12 * 80 = 960

8 * 80 = 640

--------------

difference: 320

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A playground with 4 sides has a perimeter of 73 feet. Three sides of it are 14 feet,19 feet and 25 feet what is the length of th
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3 years ago
Please help me Please this is due today
Tasya [4]

Answer:

See Below.

Step-by-step explanation:

By the Factor Theorem, if we divide <em>q(x)</em> into <em>p(x) </em>and the resulting remainder is 0, then <em>p(x)</em> is divisible by <em>q(x)</em> (i.e. there are no remainders).

Problem 1)

We are given:

p(x)=x^3+3x^2+3x+1\text{ and } q(x)=x+1

We should find the remainder when dividing <em>p(x)</em> and <em>q(x)</em>. We can use the Polynomial Remainder Theorem. When dividing a polynomial <em>p(x)</em> by a binomial in the form of (<em>x</em> - <em>a</em>), then the remainder will be <em>p(a).</em>

Here, our divisor is (<em>x</em> + 1) or (<em>x</em> - (-1)). So, <em>a </em>= -1.

Then by the Polynomial Remainder Theorem, the remainder when performing <em>p(x)/q(x)</em> is:

p(-1)=(-1)^3+3(-1)^2+3(-1)+1=0

The remainder is 0, satisfying the Factor Theorem. <em>p(x)</em> is indeed divisible by <em>q(x)</em>.

Problem 2)

We are given:

p(x)=x^3-2x^2+6x-27\text{ and } q(x)=x-3

Again, use the PRT. In this case, <em>a</em> = 3. So:

p(3)=(3)^3-2(3)^2+6(3)-27=0

It satisfies the Factor Theorem.

Problem 3)

We are given:

p(x)=x^n-10^n\text{ and } q(x)=x-10

Use the PRT. In this case, <em>a</em> = 10. So:

p(10)=(10)^n-10^n=0

It satisfies the Factor Theorem.

Since all three cases satisfy the Factor Theorem, <em>p(x)</em> is divisible by <em>q(x)</em> in all three instances.

7 0
3 years ago
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