Answer:
Answer:
a).
The amount spent on school materials for each term of all ST201students
b).
a).
It is not a random sample. This looks like a convenience sampling and there is sampling bias. This sample is not representative of the entire population. Since it is not a random sample it is not appropriate to generalize the results to all students.
b).
The sample size is 80 which is greater than 30. It is large enough to assume normal distribution according to central limit theorem.
c).
mean: $617
z critical value at 95%: 1.96
standard error = σ/sqrt(n) =500/sqrt(80) = 55.9017
lower limit= mean-1.96*se = 617-1.96*55.9017=507.43
upper limit= mean+1.96*se = 617+1.96*55.9017=726.57
d).
The amount spent on school materials for each term for the 80 ST201students is $617. We are 95% confident that amount spent on school materials for each term of all ST201students falls in the interval ($507.43, $726.57).
Step-by-step explanation:
Answer:
B. 30 units³
Step-by-step explanation:
the volume= 5×2×3 = 30
So, to factorise something you are taking out the highest common factor.Here, 10 is an example of the highest common factor (I’ll refer to this as HCF)
10(2k+5)
Everything inside the brakets is multiplied by what’s directly next to it (if there is a negative sign, then that is included). So, 10 x 2k = 20k and 10 x 5 = 50
10(2k + 5) is the factorised version of 20k + 50
Answer:
First, let’s calculate the money Sam makes per week, not including sales (or assuming $0 in sales):
money per week =$6.45/hour×37.5hours/week=$241.88/week
The money he gains from sales must make up the difference, so
money from sales =$400−$241.88=$158.12
This money is only 6% or 0.06 of the total sales though, so
total sales =$158.120.06=$2635.33
Of course, this is assuming that the money per week is rounded up from $241.875 to $241.88 instead of down to $241.87, in which case Sam would have to make $2635.50 in sales (about 17 cents more).
