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2 years ago

PLEASE HELP WILL MARK BRAINLIEST !!!

Mathematics

1 answer:

tresset_1 [31]2 years ago

6 0

Answer:

Step-by-step explanation:

i say 3 :I

cuz theres 3 dots spreed out and it said to connect the dots by starting off one and connect the others so i think its 3

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Pls Help i dont understand ittttttttttt

agasfer [191]

The given scale for the map means that a distance of 1 cm between two locations on the map corresponds to a real distance between them of 600,000 cm = 6 km.

So, if the distance between two places in reality is 87 km, on the map this would be represented by a distance of 14.5 cm, since

87 = 84 + 3

87 = 6 • 14 + 6 • (1/2)

87 = 6 • (14 + 1/2)

3 0

2 years ago

What is the complement and the supplement of 52 degrees

motikmotik

Complimentary angles add up to 90 degrees and supplementary angles add up to 180 degrees...

Complementary angle = 90-52= 38°

Supplementary angle = 180-52= 128°

4 0

3 years ago

Can you please help?

yan [13]

Answer:

f = (9c/5) + 32

Step-by-step explanation:

im pretty sure maybe

8 0

3 years ago

Line passing through (2,5) and the m= -5/6

kiruha [24]

Answer:

y - 5 = (-5/6)(x - 2)

y - 5 = (-5/6)x + 10/6

y - 30/6 = (-5/6)x + 10/6

y = (-5/6)x + 20/3

Step-by-step explanation:

5 0

3 years ago

Let z denote a random variable that has a standard normal distribution. Determine each of the probabilities below. (Round all an

Gelneren [198K]

Answer:

(a) P (Z < 2.36) = 0.9909 (b) P (Z > 2.36) = 0.0091

(e) P (-0.77< Z > -0.55) = 0.0705 (f) P (Z > 3) = 0.0014

(g) P (Z > -3.28) = 0.9995 (h) P (Z < 4.98) = 0.9999.

Step-by-step explanation:

Let us consider a random variable, $X \sim N (\mu, \sigma^{2})$ , then $Z=\frac{X-\mu}{\sigma}$ , is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, $Z \sim N (0, 1)$ .

In statistics, a standardized score is the number of standard deviations an observation or data point is above the mean. The z-scores are standardized scores.

The distribution of these z-scores is known as the standard normal distribution.

(a)

Compute the value of P (Z < 2.36) as follows:

P (Z < 2.36) = 0.99086

≈ 0.9909

Thus, the value of P (Z < 2.36) is 0.9909.

(b)

Compute the value of P (Z > 2.36) as follows:

P (Z > 2.36) = 1 - P (Z < 2.36)

= 1 - 0.99086

= 0.00914

≈ 0.0091

Thus, the value of P (Z > 2.36) is 0.0091.

(c)

Compute the value of P (Z < -1.22) as follows:

P (Z < -1.22) = 0.11123

≈ 0.1112

Thus, the value of P (Z < -1.22) is 0.1112.

(d)

Compute the value of P (1.13 < Z > 3.35) as follows:

P (1.13 < Z > 3.35) = P (Z < 3.35) - P (Z < 1.13)

= 0.99960 - 0.87076

= 0.12884

≈ 0.1288

Thus, the value of P (1.13 < Z > 3.35) is 0.1288.

(e)

Compute the value of P (-0.77< Z > -0.55) as follows:

P (-0.77< Z > -0.55) = P (Z < -0.55) - P (Z < -0.77)

= 0.29116 - 0.22065

= 0.07051

≈ 0.0705

Thus, the value of P (-0.77< Z > -0.55) is 0.0705.

(f)

Compute the value of P (Z > 3) as follows:

P (Z > 3) = 1 - P (Z < 3)

= 1 - 0.99865

= 0.00135

≈ 0.0014

Thus, the value of P (Z > 3) is 0.0014.

(g)

Compute the value of P (Z > -3.28) as follows:

P (Z > -3.28) = P (Z < 3.28)

= 0.99948

≈ 0.9995

Thus, the value of P (Z > -3.28) is 0.9995.

(h)

Compute the value of P (Z < 4.98) as follows:

P (Z < 4.98) = 0.99999

≈ 0.9999

Thus, the value of P (Z < 4.98) is 0.9999.

**Use the z-table for the probabilities.

3 0

3 years ago