If I understand what you are asking, you can use the median as an average since it is not affected by the mean ( median is a measure of center). Since a mean is affected by outliers, it might lower the score if there are very low outliers. But note that if there are outliers way <em>greater </em>it can increase the average. You can use the Inter Quartile Range if shown on a box plot ( measure of variability).
Answer:
.89/8=.11
2.39/32=.07
Step-by-step explanation:
.89/8=.11
2.39/32=.07
Answer:
37.7
Step-by-step explanation:
The orginal answer is 37.699
But you want to round the tenth
So 9 to the 6 you want to rasie the score
6 turns into a 7 and the numbers behind it (9 and the other 9) turn into a zero
37.7 or 37.700
Complementary angles
Adjacent angles
Correct
The student is incorrect, the actual x-intercept is (5, 0).
<h3>Is the student correct or incorrect?</h3>
Here we have the equation:
x + 2y = 5
The student says that the x-intercept is the point (0, 5).
So if you look at the point you already can see that the student is incorrect, this is because the x-intercept always must have a y-value of 0. (the graph only intercepts the x-axis when y = 0).
So the point (0, 5) can't be an x-intercept.
For the given function:
x +2y = 5
The x-intercept is given by:
x + 2*0 = 5
x = 5
So it is (5 , 0).
If you want to learn more about x-intercepts:
brainly.com/question/3951754
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