One number = x
Another number = y
x = y + 5
x + y = 37
(y + 5) + y = 37
2y + 5 = 37
2y = 32
y = 16
x = (16) + 5
x = 21
The numbers are 16 and 21.
This is your answer <span>33 x 33 = 4^3 = 64</span>
Step-by-step explanation:
You're asking why
let's transpose the first equation for y
-2x-6y=18
-6y=18+2x
6y=-18-2x
y=-18/6-2x/6
y=-3-⅓x as required
Pythagorean theorem.
a^2+b^2=c^2
This means that the square of the length of the 2 legs of a right triangle added together = the square of the length of the hypotenuses or diagonal.
If you know 2 of the values in the 3 variables a,b,c what would you do to find the missing variable value?
I will not write the exact answers to this problem. I think you can figure how to write it out yourselves.
Answer:
−9+16
Step-by-step explanation:
1. 10−3(3−2)
10−9+6
2. Add the numbers
3. Rearrange terms
