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2 years ago

Consider the equation below (in screenshot)

Mathematics

1 answer:

frozen [14]2 years ago

7 0

The <em>approximate</em> solution of the equation shown in the picture is x ≈ 39 / 8 (Right choice: B).

<h3>How to find an approximate solution of a one-variable equation</h3>

The solution of the equation is between x = 4 and x = 5. Now we begin by evaluating each side of the expression (f(x) = x² - 5 · x + 4, g(x) = 2 / (x - 1)) at the average of x = 4 and x = 5.

x = (4 + 5) / 2

x = 4.5

f(4.5) = 4.5² - 5 · 4.5 + 1

f(4.5) = - 5 / 4

g(4.5) = 2 / (4.5 - 1)

g(4.5) = 4 / 7

The solution of the equation is between x = 4.5 and x = 5, then we evaluate at the average:

x = (4.5 + 5) / 2

x = 4.75

f(4.75) = 4.75² - 5 · 4.75 + 1

f(4.75) = - 3 / 16

g(4.75) = 2 / (4.75 - 1)

g(4.75) = 8 / 15

The solution of the equation is between x = 4.75 and x = 5, then we evaluate at the average:

x = (4.75 + 5) / 2

x = 4.875

f(4.875) = 4.875² - 5 · 4.875 + 1

f(4.875) = 25 / 64

g(4.875) = 2 / (4.875 - 1)

g(4.875) = 16 / 31

The <em>approximate</em> solution of the equation shown in the picture is x ≈ 39 / 8 (Right choice: B).

To learn more on successive approximations: brainly.com/question/27191494

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Phoenix [80]

Answer:

13/26

Step-by-step explanation:

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3 years ago

At the end of year X, automobile installment credit accounted for 36 percent of all outstanding consumer installment credit. At

murzikaleks [220]

Answer:

option (c) 475

Step-by-step explanation:

let the automobile installment credit be 'C'

Given:.

Automobile installment credit accounted for 36 percent of all outstanding consumer installment credit

Now,

57 billion is $\frac{1}{3}$ of automobile installment credit

57 billion = $\frac{1}{3}$ × C

C = 57 × 3

C = 171 billion

now,

installment credit accounted = 36% of all outstanding consumer installment credit

171 billion = 0.36 × all outstanding consumer installment credit

All outstanding consumer installment credit = $475 billion

Hence, the correct answer is option (c) 475

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4 years ago

What is the perimeter of rhombus WXYZ?

oksian1 [2.3K]

<u>Answer</u>:

The perimeter of rhombus WXYZ is $4 \sqrt{13}$

<u>Step-by-step explanation:</u>

Step 1 :Finding length of XY

Distance formula = $\sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}$

here

$x_1$ = 5

$x_2$ =3

$y_1$ = -1

$y_2$ =2

XY = $\sqrt{(3-5)^2 +(2 -(-1))^2}$

XY = $\sqrt{(3-5)^2 +(2 +1))^2}$

XY = $\sqrt{(-2)^2 +(3))^2}$

XY = $\sqrt{4 +9}$

XY = $\sqrt{(13)}$

Step 2 :Finding length of YZ

Distance formula = $\sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}$

here

$x_1$ = 3

$x_2$ =5

$y_1$ = 2

$y_2$ =5

YZ = $\sqrt{(5-3)^2 +(5-2)^2}$

YZ = $\sqrt{(2)^2 +(3)^2}$

YZ = $\sqrt{4 +9}$

YZ = $\sqrt{(13)}$

Step 3 : :Finding length of ZW

Distance formula = $\sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}$

here

$x_1$ = 5

$x_2$ =7

$y_1$ = 5

$y_2$ =2

ZW = $\sqrt{(7-5)^2 +(5-2)^2}$

ZW = $\sqrt{(2)^2 +(3)^2}$

ZW = $\sqrt{4 +9}$

ZW = $\sqrt{(13)}$

Step 4 :Finding length of WX

Distance formula = $\sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}$

here

$x_1$ = 7

$x_2$ =5

$y_1$ = 2

$y_2$ = -1

WX = $\sqrt{(7-5)^2 +((-1)-2)^2}$

WX = $\sqrt{(2)^2 +(-3)^2}$

WX = $\sqrt{4 +9}$

WX = $\sqrt{(13)}$

Step 5: finding the perimeter of the rhombus

Perimeter= 4 X side

=> $4 \times \sqrt{13}$

=> $4 \sqrt{13}$

5 0

3 years ago

Read 2 more answers

Help me, I need to answer a question: 50% of 15

harkovskaia [24]

50% is exactly half, so to find half of something you just divide it by 2= 7.5

Or you could multiply it

15 x 0.50=7.5

4 0

3 years ago

Read 2 more answers

The scale on a map reads 1/2 inch = 75 miles. If the distance between two cities on the map is 3 and 1/4 inches, find the actual

muminat

Answer:

487.5 miles

Step-by-step explanation:

since 1/2 inch represents 75 miles and the distance is 3 1/4 inches you need to mulitply 75 X 6 = 450 and then divide 75/2=37.5 then add the two totals

450 + 37.5 = 487.5 miles

3 0

4 years ago