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3 years ago

1) Given the equation ax + 3 2 = 6, solve for x.

2 answers:

7 0

$ax+32=6$
subtract 32 from both sides
$ax+32-32=6-32$
simplify
$ax=-26$
divide both sides by a
$\frac{ax}{a}= \frac{-26}{a}$
simplify
$x=- \frac{26}{a}$
Hope this helps

ruslelena [56]3 years ago

4 0

Ax + 32 = 6
- 32 = -32
---------------------
ax = -26
---- -----
a a

1x = -26
-----
a

x = -26
-----
a

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The scale on a map is stated as 1:100000. On the map, Jennifer estimates that the distance to her destination is 8cm. If she is

Gnoma [55]

Answer:

8km

Step-by-step explanation:

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3 years ago

¿CUAL ES EL PERIMETRO DE UN RECTANGULO SABIENDO QUE SU ANCHO ES 3/4 DEL LARGO Y BEL LARGO MIDE 2,55M?

m_a_m_a [10]

Answer:

Perímetro = 8.925 metros

Step-by-step explanation:

La formula del perímetro de un rectángulo es:

perímetro = 2(ancho + largo)

en este caso:

p = 2(a+b)

a = 3b/4

b = 2.55m

a = ancho del rectángulo

b = largo del rectángulo

entonces:

sustituyendo el valor de la segunda ecuación

p = 2((3b/4)+b)

p = 2((3b/4)+(4b/4))

p = 2(7b/4)

p = 14b/4

p = 7b/2

p = 7*2.55/2

p = 8.925m

3 0

3 years ago

Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate

kolbaska11 [484]

Answer:

You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality $x^{2}-5x+4\leq 0$ . To do that, factorize, then we have that $(x-4)(x-1)\leq 0$ . This implies that

$x-1\leq 0\, \text{and}\, x-4\geq 0$

$x-1 \geq 0\, \text{and}\, x-4\leq 0$

In the first case the solution is the empty set $\emptyset$ . In the second case the solution is the interval $1\leq x \leq 4$ . Now we have that

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$B=(3,5)$

$C=(3,4]$ .

To show that $A\cap B\subseteq C$ consider $x\in A\cap B$ . Then $1\leq x \leq 4\, \text{and}\, 1$ , this implies that $3$ , then $x\in C$ . Now, to show that $C\subseteq A\cap B$ consider $x\in C$ , then $3$ , then $1\leq x \leq 4\, \text{and}\, 3$ , then $x\in [1,4] \, \text{and}\, x\in (3,5)$ , this implies that $x\in A\cap B$ .