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BARSIC [14]
1 year ago
10

What is the measure of segment PG?

Mathematics
1 answer:
agasfer [191]1 year ago
6 0

The measure of the segment PG is mathematically given as

P G=17units. Option D

<h3>What is the measure of the segment PG?</h3>

Generally, the equation for is  mathematically given as

In $\triangle G H T$ \& $\triangle G J T$

\begin{aligned}&\angle G J T=\angle G H T \quad\left(\text { each } 90^{\circ}\right) \\\\&\angle G T J=\angle H T G\end{aligned}

G T=$ G $T$ (common)

Hence \triangle G H T=\triangle G J T$ (By AAS criteria)

G H=G J$ By cpct

It is given that

$\mathrm{GH}=x+3$$$

\ln =2 x-1

Hence$G H=x+3=2 x-1$$$

\text { as given } \begin{aligned}P G &=4 x+1 \\&=4 \times 4+1 \\&=17 \\\text {  } & P G=17 \text { units }\end{aligned}

In conclusion, The measure of the segment PG is given as

P G=17

Read more about the segment

brainly.com/question/17430860

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Answer:

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Step-by-step explanation:

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3 years ago
Would the sum of -13 and 20 be positive or negative? Explain your reasoning. Use complete sentences.
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Answer:

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Step-by-step explanation:

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6 0
3 years ago
Suppose you can factor x^2 +bx +c as (x+p)(x+q) . If c&lt;0, what could be the possible values of p and q?
Anna11 [10]
Ans: Option A

Explanation:
Let's solve it smartly!
Given expression: x^{2} + bx +c --- (A)
Factors: (x+p)(x+q)
Condition: c<0
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By comparing (B) with (A), we can say that:
pq = c --- (C)

Now, as the condition says, c<0, it means either p or q is negative. Both cannot be positive or both cannot be negative.

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Hence, option B and D are wrong.

2) If p<0, q<0 it means c>=0 since (-p)(-q) = (+c)(according to equation (C)). Condition is not met.
Hence option C is out as well.

We are left with Option A:p<0, q>0 it means c<0 since (-p)(+q) = (-c)(according to equation (C)).
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Ans: Option A: p= -3, q= 7
4 0
3 years ago
Read 2 more answers
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1800

Step-by-step explanation:

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6 0
2 years ago
a parking lot contains (2 wheels) and cars (4 wheels). There are 35 vehicles and 114 wheels. How many motorcycles amd cars are t
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Answer:

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Solve the first equation for either variable...

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Now plug that value into either original equation to solve for y...

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