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3 years ago

Is the sum of 4.2 and 2 squared irrational or rational ?

Mathematics

2 answers:

RUDIKE [14]3 years ago

4 0

Rational because it would be 8.2

Effectus [21]3 years ago

3 0

4.2 is a rational number and the square root of 2 is a irrational number. The sum of a rational number is a irrational number is alwayd irrational.

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The height of five soldiers included 60inches,67inches,65inches and 64inches,if the mean of the five soldiers is 65inches what i

Nadya [2.5K]

Answer:

The last guy's height is 69 inches

Step-by-step explanation:

mean=sum of all numbers/number of numbers

There are 5 numbers in the set which means that 65 is the sum of all five numbers divided by 5. To reverse that we multiply 65 by 5 to get the sum of all of the numbers.

$65*5=325$

325 is the sum of all of the numbers so to find the missing number you add up all of the known numbers in the set and find the difference between that sum and 325.

$60+67+65+64=256$

$325-256=69$

The missing guy's height is 69 inches.

3 0

3 years ago

Pls help me quickly

Eduardwww [97]

9^3 is in exponential form

8 0

3 years ago

Which step should be used to prove that point P is equidistant from points R and Q

nydimaria [60]

Step-by-step explanation:

1. If any one side and any one common angle are equal in triangles PQR and PRS, then their corresponding sides are also equal.

2. If two sides and one included angle are equal in triangles PQS and PRS, then their third sides are equal.

3. In triangles PQR and PQS, if one side and one angle are equal, then their corresponding sides and angles are also equal.

4. In triangles PRS and PQS, all three angles are equal.

6 0

3 years ago

Given the following roots build a polynomial function in standard form: -3 and +2

swat32

Answer:

f(x) = x² +x -6

Step-by-step explanation:

The standard form will look like ...

f(x) = x² +bx +c

where b is the opposite of the sum of the roots, and c is their product.

f(x) = x² -(-3+2)x +(-3)(2)

f(x) = x² +x -6

_____

<em>Additional comment</em>

In general, "standard form" is ax²+bx+c. In this case, the coefficient 'a' can be 1 since neither of the roots is expressed as a fraction. The sum of roots is (-b/a) and the product of roots is (c/a).

3 0

3 years ago

April worked 1 1/2 times as long on her math project as did Carl. Debbie worked 1 1/4 times as long as Sonia. Richard worked 1 3

vlada-n [284]

Answer:

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = $5\frac{1}{4}\ hrs$

$5\frac{1}{4}\ hrs$ can be Rewritten as $\frac{21}{4}\ hrs$

Number of Hours Carl worked on Math project = $\frac{21}{4}\ hrs$

Number of Hours Sonia worked on Math project = $6\frac{1}{2}\ hrs$

$6\frac{1}{2}\ hrs$ can be rewritten as $\frac{13}{2}\ hrs$

Number of Hours Sonia worked on Math project = $\frac{13}{2}\ hrs$

Number of Hours Tony worked on Math project = $5\frac{2}{3}\ hrs$

$5\frac{2}{3}\ hrs$ can be rewritten as $\frac{17}{3}\ hrs.$

Number of Hours Tony worked on Math project = $\frac{17}{3}\ hrs.$

Now Given:

April worked $1\frac{1}{2}$ times as long on her math project as did Carl.

$1\frac{1}{2}$ can be Rewritten as $\frac{3}{2}$

Number of Hours April worked on math project = $\frac{3}{2}$ $\times$ Number of Hours Carl worked on Math project

Number of Hours April worked on math project = $\frac{3}{2}\times \frac{21}{4} = \frac{63}{8}\ hrs \ \ Or \ \ 7\frac{7}{8} \ hrs$

Also Given:

Debbie worked $1\frac{1}{4}$ times as long as Sonia.

$1\frac{1}{4}$ can be Rewritten as $\frac{5}{4}$ .

Number of Hours Debbie worked on math project = $\frac{5}{4}$ $\times$ Number of Hours Sonia worked on Math project

Number of Hours Debbie worked on math project = $\frac{5}{4}\times \frac{13}{2}= \frac{65}{8}\ hrs \ \ Or \ \ 8\frac{1}{8}\ hrs$

Also Given:

Richard worked $1\frac{3}{8}$ times as long as tony.

$1\frac{3}{8}$ can be Rewritten as $\frac{11}{8}$

Number of Hours Richard worked on math project = $\frac{11}{8}$ $\times$ Number of Hours Tony worked on Math project

Number of Hours Debbie worked on math project = $\frac{11}{8}\times \frac{17}{3}= \frac{187}{24}\ hrs \ \ Or \ \ 7\frac{19}{24}\ hrs$

Hence We will match each student with number of hours she worked.

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

5 0

3 years ago

Read 2 more answers