How many solutions does the equation have?
2 answers:
You might be interested in
Answer:
f(x) = (x -2)(x -1+3i)(x -1-3i)
Step-by-step explanation:
You can use synthetic division to find the remaining quadratic factor in the cubic. Then any of the usual means of solving the quadratic will help you find its linear factors.
In the attached, I show the synthetic division, the factoring to real numbers, and the solution that finds the complex linear factors by completing the square.
Of course, you know that for zeros a, b, and c, the linear factors are ...
f(x) = (x -a)(x -b)(x -c)
Here, we have a=2, b=1-3i, c=1+3i.
f(x) = (x -2)(x -1+3i)(x -1-3i)
