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liubo4ka [24]
2 years ago
15

0. 34 ll of hno3hno3 is titrated to equivalence using 0. 14 ll of 0. 1 mnaohmnaoh. what is the concentration of the hno3hno3 ?

Chemistry
1 answer:
Sphinxa [80]2 years ago
6 0

When 0.34 of HNO₃ is titrated to equivalence using 0.14 l of 0.1 m NaOH then the concentration of HNO₃ is 0.041 M

The reaction of neutralization of HNO₃ with NaOH is

HNO₃ + NaOH → H₂O + NaNo₃

When 1 mole of HNO₃ react with 1 mole of NaOH, based on chemical rection the moles of NaOH at equivalence point are equal to moles of HNO₃ present in solution: -

With the mole and volumes, we can find molarity as follows:

            Moles of NaOH = moles HNO₃

            ⁼ 0.14 L X (0.1 mol NaOH/L) = 0.014 mole NaOH

            =0.014 mol HNO₃

Molarity: -

              \frac{(Mole of HNO₃)}{(volume of HNO₃)}=  \frac{0.014}{0.34}

               = 0.041 M

Thus, from above solution we concluded that the concentration of HNO₃ solution is 0.041 M.

Learn more about molarity: brainly.com/question/8732513

#SPJ4

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Answer:

This question is incomplete, here's the complete question:

Consider a solution that is 2.1×10−2 M in Fe2+ and 1.6×10−2 M in Mg2+.

Part A

If potassium carbonate is used to selectively precipitate one of the cations while leaving the other cation in solution, which cation will precipitate first? ANSWER: Fe 2+

Part B

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3.07 x 10-11 = [Fe2+](4.3 x 10-4)

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