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Natasha_Volkova [10]
2 years ago
15

A água oxigenada é uma solução que contém a substância peróxido de hidrogênio.Ela é usada como bactericida.Quando aplicamos a ág

ua oxigenada em um ferimento,podemos observar a intensa formação de bolhas.Isso ocorre porque temos uma enzima chamada catalase. Ela não participa da reação química,mas leva a rápida reação de decomposição do peróxido de hidrogênio em água e em gás oxigênio.Escreva a equação química que representa a transformação descrita no texto
Chemistry
1 answer:
Svetllana [295]2 years ago
8 0

Answer:

Ver explicacion

Explanation:

Como se mencionó en la pregunta, un catalizador aumenta la velocidad de una reacción pero él mismo no participa en la reacción.

La descomposición del peróxido de hidrógeno se muestra mediante la ecuación;

2H2O2 (l) ------> 2H2O (l) + O2 (g)

La enzima involucrada en el proceso es la catalasa.

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The standard emf for the cell using the overall cell reaction below is +2.20 V:
ANEK [815]

Answer:

emf generated by cell is 2.32 V

Explanation:

Oxidation: 2Al-6e^{-}\rightarrow 2Al^{3+}

Reduction: 3I_{2}+6e^{-}\rightarrow 6I^{-}

---------------------------------------------------------------------------------

Overall: 2Al+3I_{2}\rightarrow 2Al^{3+}+6I^{-}

Nernst equation for this cell reaction at 25^{0}\textrm{C}-

E_{cell}=E_{cell}^{0}-\frac{0.059}{n}log{[Al^{3+}]^{2}[I^{-}]^{6}}

where n is number of electrons exchanged during cell reaction, E_{cell}^{0} is standard cell emf , E_{cell} is cell emf , [Al^{3+}] is concentration of Al^{3+} and [Cl^{-}] is concentration of Cl^{-}

Plug in all the given values in the above equation -

E_{cell}=2.20-\frac{0.059}{6}log[(4.5\times 10^{-3})^{2}\times (0.15)^{6}]V

So, E_{cell}=2.32V

3 0
2 years ago
You believe you have cracked a secret code that uses elemental symbols to spell words. The code uses numbers to designate the el
Stells [14]

Explanation:

Atomic numbers for neutral atoms are the same as the number of electrons. The number of electrons are used in writing the subshell notation where we can see the highest princpal quantum number(n).

In order to solve this problem, a good knowledge of the periodic table and shell notation is required.  

For example;  

  Given a number 5;  

     We know the number is made of both the atomic number of the element and the highest quantum number.  

  It is easier for us to know the highest quantum number from the shell notation:  

        shell notation 1s²2s²2p¹

        highest principal quantum number is 2

  We are left with atomic number 5-2, which is 3

           The element is therefore Li.  

Part A.   5,     30,      58,      56,     99,     79,    19,     98,     9

             Li       Fe        I         Sb       U       Ta      S      Pa     N

Part B.   9,    99,    30,     95,     19,     47,     79

             N      U       Fe      Ra      S       Mo     Ta

Learn more:  

s-orbital brainly.com/question/9288609

#learnwithBrainly

4 0
3 years ago
.325 mol KOH to grams
lesya [120]
The answer is 18.23432 grams.

Molar mass of KOH= 56.1056

( \frac{1 mol}{56.1056 grams})  (\frac{.325 mol}{x grams}) = 18.234 grams
5 0
2 years ago
The following are formed as white precipitates in solution except
aniked [119]

Answer:

A. Iron (III) hydroxide

Explanation:

Orange-brown or rust

6 0
2 years ago
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- Berikan satu contoh organ. Ramalkan keadaan manusia jika kehilangan organ tersebut
harina [27]

Answer:

Misalnya organ itu adalah kedua tangan kita,maka keadaan suatu manusia tsb tdk akan mempunyai kedua lengannya dan otomatis ia jg sulit untuk melakukan aktivitas sprti: makan,minum,mengambil sesuatu,menulis,dll

Explanation:

6 0
3 years ago
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