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frosja888 [35]
3 years ago
5

The radius of a helium atom is a 31 PM. What is the radius in nanometers?

Chemistry
1 answer:
Paladinen [302]3 years ago
7 0

Answer:

Thus, the radius of the helium atom in nanometers is - 0.031 nm

Explanation:

Given that:-

The radius of the helium atom = 31 pm

Considering the conversion of length in pm to the length in nm as:-

1 pm = 0.001 nm

So,

Applying the above conversion factor in the radius of helium atom as:-

Radius = 31\times 0.001 nm = 0.031 nm

<u>Thus, the radius of the helium atom in nanometers is - 0.031 nm</u>

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A compound is found to have 55.7% hafnium+and+44.3%+chlorine.+what+is+the+empirical+formula?
uranmaximum [27]

The empirical formula of a compound found to have 55.7% hafnium and 44.3% chlorine is HfCl4.

<h3>How to calculate empirical formula?</h3>

The empirical formula of a compound is a notation indicating the ratios of the various elements present in a compound, without regard to the actual numbers.

The empirical formula of the given compound can be calculated as follows:

  • Hafnium = 55.7% = 55.7g
  • Chlorine = 44.3% = 44.3g

First, we convert mass values to moles by dividing by the molar mass of each element

  • Hafnium = 55.7g ÷ 178.49g/mol = 0.312mol
  • Chlorine = 44.3g ÷ 35.5g/mol = 1.25mol

Next, we divide each mole value by the smallest

  • Hafnium = 0.312 ÷ 0.312 = 1
  • Chlorine = 1.25 ÷ 0.312 = 4

Therefore, the empirical formula of a compound found to have 55.7% hafnium and 44.3% chlorine is HfCl4.

Learn more about empirical formula at: brainly.com/question/14044066

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1 year ago
Help not to sure what its asking I thought it was 2 but there ain't a 2 ​
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A homogeneous mixture is made by dissolving some salt in a beaker of water. The mixture is referred to as a
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V=m/D
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D=3 g/ml
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7 0
3 years ago
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