The radius of a helium atom is a 31 PM. What is the radius in nanometers?
1 answer:
Answer:
Thus, the radius of the helium atom in nanometers is - 0.031 nm
Explanation:
Given that:-
The radius of the helium atom = 31 pm
Considering the conversion of length in pm to the length in nm as:-
1 pm = 0.001 nm
So,
Applying the above conversion factor in the radius of helium atom as:-
Radius = nm = 0.031 nm
<u>Thus, the radius of the helium atom in nanometers is - 0.031 nm</u>
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<u>Answer:</u> The mass of potassium bromide present in 41.2 mL of solution will be 3.522 grams.
<u>Explanation:</u>
We are given that KBr is present in 8.3% KBr solution, which means that 8.3 grams of potassium bromide is present in 100 gram of the solution.
To calculate the volume of KBr, we use the formula:
Mass of the solution = 100 grams
Density of KBr solution = 1.03g/mL
Volume of the solution = ? mL
Putting values in above equation, we get:
Now, to calculate the mass of KBr in 41.2mL of the solution, we use unitary method.
In 97.08 mL of solution, mass of KBr present is 8.3 grams.
So, 41.2 mL of solution will contain = of KBr.
Hence, the mass of potassium bromide present in 41.2 mL of solution will be 3.522 grams.