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frosja888 [35]
3 years ago
5

The radius of a helium atom is a 31 PM. What is the radius in nanometers?

Chemistry
1 answer:
Paladinen [302]3 years ago
7 0

Answer:

Thus, the radius of the helium atom in nanometers is - 0.031 nm

Explanation:

Given that:-

The radius of the helium atom = 31 pm

Considering the conversion of length in pm to the length in nm as:-

1 pm = 0.001 nm

So,

Applying the above conversion factor in the radius of helium atom as:-

Radius = 31\times 0.001 nm = 0.031 nm

<u>Thus, the radius of the helium atom in nanometers is - 0.031 nm</u>

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Consider the following operations on the number 7.02 times 10^-2. Without using a calculator, decide which would give a signific
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This is quite a dicey  question to analyze, let us not get too carried away with the simplicity of the mathematical signs involved.

Given that 7.02 × 10⁻² is the number to be compared with.

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(b). 7.02 × 10⁻² - 6.10 × 10⁵

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(c). 7.02 × 10⁻² × 6.10 × 10⁵

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7.02 × 10⁻² × 6.10 × 10⁵ = (7.02 × 6.10) × 10⁻²⁺⁵ = (7.02 × 6.10) × 10³

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(d). 7.02 × 10⁻² ÷ 6.10 × 10⁵

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where ⇒ (10ᵃ ÷ 10ᵇ = 10ᵃ⁻ᵇ)

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this final value gives a Significantly Smaller value

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cheers i hope this helps.

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