Find an equation of the line that passes through the given point and has the indicated slope m.
1 answer:
Answer:
y = x + 2
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Here m = , thus
y = x + c ← is the partial equation
To find c substitute (- 5, - 2) into the partial equation
- 2 = - 4 + c ⇒ c = - 2 + 4 = 2
y = x + 2 ← equation of line in slope- intercept form
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Answer:
Step-by-step explanation:
<u>Equation of a circle</u>
where:
- (a, b) is the center
- r is the radius
From inspection of the diagram, the center of the circle <em>appears</em> to be at point (-3, 2), although this is not very clear. Therefore, a = -3 and b = 2.
Substitute these values into the general form of the equation of a circle:
Again, from inspection of the diagram, the <u>maximum vertical point</u> of the circle appears to be at y = 5. Therefore, to calculate the radius, subtract the y-value of the center point from the y-value of the maximum vertical point:
⇒ radius (r) = 5 - 2 = 3
Substitute the found value of r into the equation:
Therefore, the final equation of the given circle is:
