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Lera25 [3.4K]
1 year ago
9

Rewrite in vertex form. F(x)=2x^2-20x+8

Mathematics
1 answer:
nexus9112 [7]1 year ago
6 0

The <em>vertex</em> form of the <em>quadratic</em> equation, written in <em>standard</em> form, f(x) = 2 · x² - 20 · x + 8 is f(x) + 75 = 2 · (x - 5)².

<h3>What is the vertex form of a quadratic equation?</h3>

In this problem we have a <em>quadratic</em> equation in <em>standard</em> form, whose form is defined by f(x) = a · x² + b · x + c, where a, b, c are <em>real</em> coefficients, and we need to transform it into <em>vertex</em> form, defined as:

f(x) - k = C · (x - h)²       (1)

Where:

  • (h, k) - Vertex coordinates
  • C - Vertex constant

This latter form can be found by algebraic handling. If we know that f(x) = 2 · x² - 20 · x + 8, then its vertex form is:

f(x) = 2 · x² - 20 · x + 8

f(x) = 2 · (x² - 10 · x + 4)

f(x) + 2 · 25 = 2 · (x² - 10 · x + 25)

f(x) + 75 = 2 · (x - 5)²

The <em>vertex</em> form of the <em>quadratic</em> equation, written in <em>standard</em> form, f(x) = 2 · x² - 20 · x + 8 is f(x) + 75 = 2 · (x - 5)².

To learn more on quadratic equations: brainly.com/question/1863222

#SPJ1

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Answer:

We have to find the 90% confidence interval for the mean

                 Given sample size  

                        Sample mean  

Population standard deviation  

Here the confidence level is 90% then  

                                                  And  

The 90% confidence interval is  

Here  is the critical value at 0.05

From the tables  

Now the 90% confidence interval is =

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                                                                                     =(3840.44, 4133.56)

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