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3 years ago

What is the domain of this function? y = 2x - 2

Mathematics

1 answer:

Furkat [3]3 years ago

6 0

Answer:

The domain is (-∞,∞)

Step-by-step explanation:

Since there's no limit to this function, the values are infinity.

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Which of the following statements is not true?

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The false statement is d; the quotient of two negative numbers is always negative

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3 years ago

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State the domain of the relation {(0, 5), (5, 2), (0, −4), (1, 5)}.

Sidana [21]

Answer:

ez the domain his the first number and the range is the second. so the domain here is 0,5,1 do not write two same numbers like 0 and 0 and the range is 5,2,-4 and again do not write 5 twice

Step-by-step explanation:

0,5,1 is the domain i could be wrong lol

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2 years ago

According to a survey of workers, 5/50

Otrada [13]

Answer:

45 percent like to walk or bike

Step-by-step explanation:

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3 years ago

(3y - 3) + x<br><br> X=3<br> Y= 5

xz_007 [3.2K]

Plug in 5 for y, and 3 for x

(3(5) - 3) + (3)

First, multiply

5 x 3 = 15

Next, subtract

15 - 3 = 12

Finally, add

12 + 3 = 15

15 is your answer

hope this helps

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3 years ago

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whats the equation for the perpendicular bisector of the line segment whose endpoints are (-5,3) and (3,7)?

riadik2000 [5.3K]

Answer:

The equation of perpendicular bisector of the line segment passing through (-5,3) and (3,7) is: $y = -2x+3$

Step-by-step explanation:

Given points are:

(-5,3) and (3,7)

The perpendicular bisector of line segment formed by given points will pass through the mid-point of the line segment.

First of all we have to find the slope and mid-point of given line

Here

(x1,y1) = (-5,3)

(x2,y2) = (3,7)

The slope will be:

$m = \frac{y_2-y_1}{x_2-x_1}\\m = \frac{7-3}{3+5}\\m = \frac{4}{8}\\m = \frac{1}{2}$

The mid-point will be:

$(x,y) = (\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2})\\ = (\frac{-5+3}{2},\frac{3+7}{2})\\= (\frac{-2}{2},\frac{10}{2})\\=(-1,5)$

Let m1 be the slope of the perpendicular bisector

Then using, "Product of slopes of perpendicular lines is -1"

$m.m_1 = -1\\\frac{1}{2}.m_1 = -1\\m_1 = -1*2\\m_1 = -2$

We have to find the equation of a line with slope -2 and passing through (-1,5)

The slope-intercept form is given by:

$y = mx+b\\y = -2x+b$

Putting the point (-1,5) in the equation

$5 = -2(-1)+b\\5 = 2+b\\b = 5-2\\b = 3$

The final equation is:

$y = -2x+3$

Hence,

The equation of perpendicular bisector of the line segment passing through (-5,3) and (3,7) is: $y = -2x+3$

4 0

3 years ago