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kiruha [24]
2 years ago
7

If shay has 2 apple and gets 3 more She have she how many apples cloes.​

Mathematics
1 answer:
mart [117]2 years ago
5 0

Answer:

5 apples!

Step-by-step explanation:

Shay had 2 apples at first. She then was given 3 more. So:

2 apples + 3 apples = 5 apples

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Find the critical values: a. Determine the critical value z????/2 that corresponds to a level of confidence of 87%. (2 pts). b.
larisa86 [58]

Answer:

a) z_{\alpha/2}=-1.51 and z_{\alpha/2}=1.51

b) t_{\alpha/2}=-1.89 and t_{\alpha/2}=1.89

c) t_{\alpha/2}=-2.11

d) z_{\alpha/2}=-1.75 and z_{\alpha/2}=1.75

Step-by-step explanation:

Part a

On this case the confidence is 87% or 0.87 so the significance level is \alpha=1-0.87=0.13 and \alpha/2 =0.065. On this case we can assume that is a bilateral test or a confidence interval so we will have two critical values.

We need values a,b on the normal standard distribution such that:

P(Z or P(Z>b)=0.065 and in order to find it we can use the following code in excel:

"NORM.INV(0.065,0,1)" or "NORM.INV(1-0.065,0,1)", and we see that the critical values z_{\alpha/2}=-1.51 and z_{\alpha/2}=1.51

Part b

On this case the confidence is 92% or 0.92 so the significance level is \alpha=1-0.92=0.08 and \alpha/2 =0.04. On this case we can assume that is a bilateral test or a confidence interval so we will have two critical values.

First we need to calculate the degrees of freedom given by:

df=n-1=15-1=14

We need values b,c on the t distribution with 14 degrees of freddom such that:

P(t_{(14)} or P(t_{(14)}>c)=0.04 and in order to find it we can use the following code in excel:

"T.INV(0.04,14)" or "T.INV(1-0.04,14)", and we see that the critical values t_{\alpha/2}=-1.89 and t_{\alpha/2}=1.89

Part c

The significance level is \alpha=0.025 and is a left tailed test. On this case we know that is a left tailed test so then we have just one critical value.

First we need to calculate the degrees of freedom given by:

df=n-1=18-1=17

We need a value c on the t distribution with 17 degrees of freddom such that:

P(t_{(17)}, and in order to find it we can use the following code in excel:

"T.INV(0.025,17)", and we see that the critical values t_{\alpha/2}=-2.11

Part d

The significance level is \alpha=0.08 and \alpha/2 =0.04. On this case we know that w ehave a two tailed proportion test, so we will have two critical values.

We need values a,b on the normal standard distribution such that:

P(Z or P(Z>b)=0.04 and in order to find it we can use the following code in excel:

"NORM.INV(0.04,0,1)" or "NORM.INV(1-0.04,0,1)", and we see that the critical values z_{\alpha/2}=-1.75 and z_{\alpha/2}=1.75

6 0
3 years ago
the point (3,-6) lies on the terminal side of angle 0. Find the exact value of the six trigonometric functions of 0. Sin cos tan
Shkiper50 [21]

ANSWER

See explanation

EXPLANATION

The point (3,-6) is the fourth quadrant.

In this quadrant only the cosine ratio and the secant ratio are positive.

The remaining four trigonometric ratios are negative.

The diagram is shown in the attachment.

We use the Pythagoras Theorem to find the hypotenuse, h.

{h}^{2}  =  {6}^{2}  +  {3}^{2}

{h}^{2}  = 36 + 9

{h}^{2}  = 45

h =  \sqrt{45}

h = 3 \sqrt{5}

\sin( \theta)  =   -  \frac{opp}{hyp}

\sin( \theta)  =   -  \frac{6}{3 \sqrt{5} }

\sin( \theta)  =   -  \frac{2 \sqrt{5} }{ 5 }

\sin( \theta)  =   -  \frac{2}{ \sqrt{5} }

\ cos(\theta)  =   \frac{adj}{hyp}

\ cos(\theta)  =   \frac{3}{3 \sqrt{5} }

\ cos(\theta)  =   \frac{1}{ \sqrt{5} }

\ cos(\theta)  =   \frac{ \sqrt{5} }{5}

\tan(\theta)= -  \frac{opp}{hyp}

\tan(\theta)= -  \frac{6}{3}  =  - 2

\csc(\theta)= -  \frac{hyp}{opp}

\csc(\theta)= -  \frac{3 \sqrt{5} }{6}  =  -   \frac{\sqrt{5} }{2}

\sec( \theta)  =   \frac{hyp}{adj}

\sec( \theta)  = \frac{3 \sqrt{5} }{3}  =  \sqrt{5}

\cot( \theta)  =  -  \frac{adj}{opp}

\cot( \theta)  =   - \frac{3}{6}  =  - \frac{1}{2}

6 0
3 years ago
1. The rules for adding and subtracting rational expressions are the same as
Dahasolnce [82]
The answer is true because it is the same
6 0
2 years ago
What is the point-slope form of a line with slope-3 that contains the point<br> (10,-1)?
horsena [70]

Answer:

y = - 3x + 29

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - 3, thus

y = - 3x + c ← is the partial equation of the line

To find c substitute (10, - 1) into the partial equation

- 1 = - 30 + c ⇒ c = - 1 + 30 = 29

y = - 3x + 29 ← equation of line

7 0
3 years ago
Find the missing length of the triangle. *
stepladder [879]

Answer:

84mm

Step-by-step explanation:

51+45=96

1 right angle

scalene triangle

180-96=84

6 0
3 years ago
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