Using it's concept, it is found that there is a 0.125 = 12.5% experimental probability that a randomly selected preschooler would choose to read books today.
<h3>What is a probability?</h3>
A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.
For an experimental probability, these numbers of outcomes are taken from previous trials.
In this problem, in the previous trial, one out of eight students read a book, hence:
p = 1/8 = 0.125 = 12.5%.
There is a 0.125 = 12.5% experimental probability that a randomly selected preschooler would choose to read books today.
More can be learned about probabilities at brainly.com/question/14398287
Answer:
<em>793 food hampers were distributed</em>
Step-by-step explanation:
We need to find how many food hampers were distributed in a typical week, knowing that
- 200 hampers were distributed on Mondays
40 fewer hampers were distributed on Tuesdays than on Mondays, thus:
- 160 hampers were distributed on Tuesdays
on Wednesdays, the volume is 1.3 times Tuesday’s volume, thus 160*1.3=
- 208 hampers were distributed on Wednesdays
on Thursdays the number of hampers distributed was 3/4 of Monday’s volume, thus 3/4*200=
- 150 hampers were distributed on Thursdays
on Fridays, 50% of Thursday’s volume was distributed, therefore 50%*150=
- 75 hampers were distributed on Fridays
The total number of food hampers distributed in the week is
200+160+208+150+75=793
793 food hampers were distributed
Answer:
-2(9+32n)
Step-by-step explanation:
Both the 18 and 64 n are negative, and that is the only answer choice that results in two negative numbers.
Here we must see in how many different ways we can select 2 students from the 3 clubs, such that the students <em>do not belong to the same club. </em>We will see that there are 110 different ways in which 2 students from different clubs can be selected.
So there are 3 clubs:
- Club A, with 10 students.
- Club B, with 4 students.
- Club C, with 5 students.
The possible combinations of 2 students from different clubs are
- Club A with club B
- Club A with club C
- Club B with club C.
The number of combinations for each of these is given by the product between the number of students in the club, so we get:
- Club A with club B: 10*4 = 40
- Club A with club C: 10*5 = 50
- Club B with club C. 4*5 = 20
For a total of 40 + 50 + 20 = 110 different combinations.
This means that there are 110 different ways in which 2 students from different clubs can be selected.
If you want to learn more about combination and selections, you can read:
brainly.com/question/251701
Answer:
the answer may be this: 8 √3
