Consecutive integers are 1 apart
they are
x,x+1,x+2
the sum of their squares is 194
x²+(x+1)²+(x+2)²=194
expand
x²+x²+2x+1+x²+4x+4=194
x²+x²+x²+2x+4x+1+4=194
3x²+6x+5=194
minus 5 from both sides
3x²+6x=189
3(x²+2x)=189
divide both sides by 3
x²+2x=63
minus 63 from bot sides
x²+2x-63=0
what 2 numbers multiply to get -63 and add to get 2
-7 and 9
(x-7)(x+9)=0
set each to zero
x-7=0
x=7
x+9=0
x=-9
for x=7
x+1=8
x+2=9
for x=-9
x+1=-8
x+2=-7
the integers are 7,8,9 or -9,-8,-7
Answer:
52
Step-by-step explanation:
First, find x. As BE and DE will have the same measurements, you can set your formula up as
5x+11=3x+17
5x=3x+17-11
5x-2x=6
2x=6
x=6/2
x=3
CE and AE will also have the same value, now substitute 3 in place of x to get the value of segment BE
5x+11
5*3+11 = 26
This also means that CE = 26 and AE = 26
AC = CE + AE
AC = 52
Answer: x^3 + x^2 - 17x + 12
Step-by-step explanation:
(x+4)(x^2-5x+3)
x^3 - 5x^2 + <u>3x</u> + 4x^2 <u>- 20x</u> + 12
underlined and bolded can be combined
That leaves you with x^3 + x^2 - 17x + 12
Addition subtraction multiplication or division
