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Mariulka [41]
1 year ago
7

Please help me, i will give brainliest!! help me please

Mathematics
1 answer:
Minchanka [31]1 year ago
4 0

The answers are :

10) 25 : 24

11) 24 : 5

12) 36 : 5

13) 7 : 3

14) 15 : 1

<u>Ratio = Number of event 1 : Number of event 2</u> (in same unit, if necessary)

<u>10</u>

Girls preferring orange juice : Boys preferring orange juice

50 : 48 (Divide by 2 on both sides)

25 : 24

<u>11</u>

Boys preferring orange juice : Boys preferring grapefruit juice

48 : 10 (Divide by 2 on both sides)

24 : 5

Remember :

  • <u>1 minute = 60 seconds</u>
  • <u>1 week = 7 days</u>
  • <u>1 hour = 60 minutes</u>

<u />

<u>12</u>

3 minutes : 25 seconds

3 × 60 : 25 (Divide by 5 on both sides)

3 × 12 : 5

36 : 5

<u>13</u>

2 weeks : 6 days

2 × 7 : 6 (Divide by 2 on both sides)

7 : 3

<u>14</u>

5 hours : 20 minutes

5 × 60 : 20 (Divide by 20 on both sides)

5 × 3 : 1

15 : 1

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out of some students appeared in an examination 80% passed in mathematics 75% passed in english and 5% failed in both subjects i
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Answer:

5000 students appeared in the examination.

Step-by-step explanation:

We solve this question using Venn probabilities.

I am going to say that:

Event A: Passed in Mathematics

Event B: Passed in English.

5% failed in both subjects

This means that 100 - 5 = 95% pass in at least one, which means that P(A \cup B) = 0.95

80% passed in mathematics 75% passed in english

This means that P(A) = 0.8, P(B) = 0.75

Proportion who passed in both:

P(A \cap B) = P(A) + P(B) - P(A \cup B)

Considering the values we have for this problem

P(A \cap B) = P(A) + P(B) - P(A \cup B) = 0.8 + 0.75 - 0.95 = 0.6

3000 of them were passed both subjects how many students appeared in the examination?

3000 is 60% of the total t. So

0.6t = 3000

t = \frac{3000}{0.6}

t = 5000

5000 students appeared in the examination.

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