Answer:
There is no point of the form (-1, y) on the curve where the tangent is horizontal
Step-by-step explanation:
Notice that when x = - 1. then dy/dx becomes:
dy/dx= (y+2) / (2y+1)
therefore, to request that the tangent is horizontal we ask for the y values that make dy/dx equal to ZERO:
0 = ( y + 2) / (2 y + 1)
And we obtain y = -2 as the answer.
But if we try the point (-1, -2) in the original equation, we find that it DOESN'T belong to the curve because it doesn't satisfy the equation as shown below:
(-1)^2 + (-2)^2 - (-1)*(-2) - 5 = 1 + 4 + 2 - 5 = 2 (instead of zero)
Then, we conclude that there is no horizontal tangent to the curve for x = -1.
Answer:
y=(x+4)²-19
Step-by-step explanation:
Hi there!
We are looking for perpendicular angles, which means the angle between the streets is 90 degrees. So, each time we need to find the street that intersects the given street with a 90 degree angle.
On this map, Oxford Street is perpendicular to Waterloo St., and Rosewood Street is perpendicular to Oak St..
The answers are (in correct order): Waterloo St. and Oak St..
~ Hope this helps you!
Catherine has 12.
2 times 3 is 6. 6 times 2 is 12. Final answer is 12.
Answer -15 because it would be 15 but the negative would be turned into a negative again