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Serhud [2]
3 years ago
5

Help me solve for t please

Mathematics
1 answer:
cupoosta [38]3 years ago
8 0
Look at the answer down here please

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A rectangle has an area of 0.24 of a square. What are some possibility for the length and width of the rectangle? Tell why
VLD [36.1K]

Answer:

<h3>The possibilities of length and width of the rectangle are </h3><h3>x=1, y=0.24;</h3><h3>x=0.5, y=0.48;</h3><h3>x=0.25, y=0.96;</h3><h3>x=2, y=0.12</h3>

Step-by-step explanation:

Given that the area is 0.24 square meter

The area of a rectangle is given by

Area=length\times width square units

Let x be the length and y be the width.

Since the area is 0.24 square meter, we have the equation:

Area=x\times y = 0.24, with x and y measures in meters

If we want to know some possibilities of x and y, we can assume a value for one of them, and then calculate the other one using the equation.

Now choosing some values for "x", we have:

Put x = 1

1\times y = 0.24

∴ y = 0.24

Now put x = 0.5 we get

0.5\times y = 0.24

∴ y = 0.48

Put  x = 0.25

0.25\times y = 0.24

∴ y = 0.96

Put x = 2

2\times y = 0.24

∴ y = 0.12

8 0
3 years ago
Read 2 more answers
Is the sum of the
Olin [163]
Answer
Yes


Explanation
I just know
8 0
3 years ago
Which of the following describes the zeroes of the graph of f(x)= -x^5+9x^4-18x^3
Elina [12.6K]

Answer:

-x^5+9x^4-18x^3=0\\-x^3(x^2-9x+18)=0\\-x^3(x-3)(x-6)=0\\\\\\\\x=0\\x=3\\x=6

4 0
3 years ago
How would the expression x^3-8 be written using difference of cubes
ludmilkaskok [199]

we can use formula

a^3-b^3=(a-b)(a^2+ab+b^2)

we can compare

we get

a=x

b=2

now, we can plug that in formula

and we get

x^3-2^3=(x-2)(x^2+2x+2^2)

now, we can simplify it

x^3-8=(x-2)(x^2+2x+4)...........Answer

4 0
4 years ago
Read 2 more answers
If is a segment bisector of and AB = 17, find AP.
NNADVOKAT [17]

Answer:

B. 8.5

Step-by-step explanation:

It's a segment bisector which means the other line bisects the direct middle of AB. 17/2 is 8.5, meaning that AP should be 8.5

7 0
3 years ago
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