A^2+b^2=c^2 so c^2=12^2+16^2 which then simplifies to c^2=144+256 then simplify that to c^2=400. After that take the square root of c^2 and the square root of 400. So your answer is c=20
Answer: y = 80*
all circles have 360* so we can subtract what we have to get what we want
360 - 110 - 90 - 80 = 80*
Answer:
Step-by-step explanation:
Given equation:
On comparing the equation by ax² + bx + x = 0, We get: a = 1, b = 2 and c = 3
To Find the nature of the roots of the equation firstly we need to find the discriminant of the equation. The expression b²- 4ac is called the discriminant.

- Two Distinct real roots, if b² - 4ac > 0
- Two equal real roots, if b² - 4ac = 0
- No real roots, if b² - 4ac < 0

The discriminant is smaller than 0.
- <u>Hence, Equation has no </u><u>real</u><u> roots (no solution)</u>