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givi [52]
1 year ago
8

Use theorem 7. 4. 2 to evaluate the given laplace transform. do not evaluate the convolution integral before transforming. (writ

e your answer as a function of s. ) ℒ t et − d 0
Mathematics
1 answer:
irga5000 [103]1 year ago
3 0

With convolution theorem the equation is proved.

According to the statement

we have given that the equation and we have to evaluate with the convolution theorem.

Then for this purpose, we know that the

A convolution integral is an integral that expresses the amount of overlap of one function as it is shifted over another function.

And the given equation is solved with this given integral.

So, According to this theorem the equation becomes the

\mathscr{L} \left( \int_{0}^{t} e^{-\tau} \cos \tau d \tau \right) = \frac{ \mathscr{L} (e^{-\tau} \cos \tau ) }{s} \\\mathscr{L} \left( \int_{0}^{t} e^{-\tau} \cos \tau d \tau \right) = \frac{\frac{s+1}{(s+1)^2+1}}{s} \\\mathscr{L} \left( \int_{0}^{t} e^{-\tau} \cos \tau d \tau \right) = \frac{1}{s}\left (\frac{s+1}{(s+1)^2+1} \right).

Then after solving, it become and with theorem it says that the

\mathscr{L} \left( \int_{0}^{t} f(\tau) d\tau \right) = \frac{\mathscr{L} ( f(\tau))}{s} .

Hence by this way the given equation with convolution theorem is proved.

So, With convolution theorem the equation is proved.

Learn more about convolution theorem here

brainly.com/question/15409558

#SPJ4

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Bonds are a(n) _______________ instrument.
stiks02 [169]

Answer:

indebtedness

Step-by-step explanation:

3 0
3 years ago
Solve for W: P=2L + 2W<br><br>A. W=P-L<br>B. W= 1/2P - L<br>C. W= 1/2 P + L<br>D. W= 2P - L​
svetlana [45]

Answer:

B

Step-by-step explanation:

P=2L+2W

P-2L=2W (Subtract 2L from both sides of the equation)

2W=P-2L (Symmetric Property of Equality)

W=\frac{P-2L}{2} (Divide both sides of the equation by 2)

W=\frac{P}{2} -\frac{2L}{2} ("Split" the fractions)

W=\frac{1}{2}P-L (Simplify)

Hope this helps!

4 0
2 years ago
Solve using Fourier series.
Olin [163]
With 2L=\pi, the Fourier series expansion of f(x) is

\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos\dfrac{n\pi x}L+\sum_{n\ge1}b_n\sin\dfrac{n\pi x}L
\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos2nx+\sum_{n\ge1}b_n\sin2nx

where the coefficients are obtained by computing

\displaystyle a_0=\frac1L\int_0^{2L}f(x)\,\mathrm dx
\displaystyle a_0=\frac2\pi\int_0^\pi f(x)\,\mathrm dx

\displaystyle a_n=\frac1L\int_0^{2L}f(x)\cos\dfrac{n\pi x}L\,\mathrm dx
\displaystyle a_n=\frac2\pi\int_0^\pi f(x)\cos2nx\,\mathrm dx

\displaystyle b_n=\frac1L\int_0^{2L}f(x)\sin\dfrac{n\pi x}L\,\mathrm dx
\displaystyle b_n=\frac2\pi\int_0^\pi f(x)\sin2nx\,\mathrm dx

You should end up with

a_0=0
a_n=0
(both due to the fact that f(x) is odd)
b_n=\dfrac1{3n}\left(2-\cos\dfrac{2n\pi}3-\cos\dfrac{4n\pi}3\right)

Now the problem is that this expansion does not match the given one. As a matter of fact, since f(x) is odd, there is no cosine series. So I'm starting to think this question is missing some initial details.

One possibility is that you're actually supposed to use the even extension of f(x), which is to say we're actually considering the function

\varphi(x)=\begin{cases}\frac\pi3&\text{for }|x|\le\frac\pi3\\0&\text{for }\frac\pi3

and enforcing a period of 2L=2\pi. Now, you should find that

\varphi(x)\sim\dfrac2{\sqrt3}\left(\cos x-\dfrac{\cos5x}5+\dfrac{\cos7x}7-\dfrac{\cos11x}{11}+\cdots\right)

The value of the sum can then be verified by choosing x=0, which gives

\varphi(0)=\dfrac\pi3=\dfrac2{\sqrt3}\left(1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots\right)
\implies\dfrac\pi{2\sqrt3}=1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots

as required.
5 0
3 years ago
Find the value of X: 3x (-35) = 2x
kobusy [5.1K]
X=0
Pls mark brainliest
5 0
3 years ago
Please help me ASAP <br> I will give brainliest
stellarik [79]

Answer:

-23

Step-by-step explanation:

rearrange to point slope form first

slope can be fine by y2-y1/x2-x1 (im using the first 2 points)

so 13-25 = -12 and -54-(-72) = 18, and the slope is -12/18 which is -2/3

then you can use any point (i used the first point) to create the point slope form which is y-ypoint=slope(x-xpoint) and equation would be y-25=-2/3(x+72)

turn it into slope intercept form by multiplying -2/3 within the equation and adding -25 on both sides

you will get y= -2/3x-23

and the y intercept will be (0, -23)

3 0
2 years ago
Read 2 more answers
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