Question

In the regular pentagon below, if AP = 4 m and BC = 10 m, find it's area.

Answer 1

First symmetrically cut the pentagon to get 5 pieces. (So that you will get the idea that this polygon is divided into 5 triangles)

Then find the area of one of the triangles:

Area of Triangle = $\frac{1}{2} bh$

A = $\frac{1}{2}$ × 4 × 10

A = 20 m²

To find the area of the whole pentagon shape:

A = 20 × 5 = 100 m²

Hope it helps!