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3 years ago

Question 18 (1 point)

Mathematics

1 answer:

neonofarm [45]3 years ago

7 0

Answer:

nsnsjksowwwwwwwwwnwbanansnsn

Step-by-step explanation:

67118/5261717=722282.622

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Twenty- four divided by the difference between 1 1/2 and 3/4

NISA [10]

Answer:

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

A colony of bacteria is growing at a rate of 0.2 times its mass. Here time is measured in hours and mass in grams. The mass of t

11Alexandr11 [23.1K]

Answer:

Question 1: $dm/dt=0.2m$

Question 2: $m=Ae^{(0.2t)}$

Question 3: $m=10e^{(0.2t)}$

Question 4: $m=10g$

Explanation:

Question 1: Write down the differential equation the mass of the bacteria, m, satisfies: m′= .2m

a) By definition: $m'=dm/dt$

b) Given: $rate=0.2m$

c) By substitution: $dm/dt=0.2m$

Question 2: Find the general solution of this equation. Use A as a constant of integration.

a) Separate variables

$dm/m=0.2dt$

b) Integrate

$\int dm/m=\int 0.2dt$

$ln(m)=0.2t+C$

c) Antilogarithm

$m=e^{0.2t+C}$

$m=e^{0.2t}\cdot e^C$

$e^C=A\\\\m=Ae^{(0.2t)}$

Question 3. Which particular solution matches the additional information?

Use the measured rate of 4 grams per hour after 3 hours

$t=3hours,dm/dt=4g/h$

First, find the mass at t = 3 hours

$dm/dt=0.2m\\\\4=0.2m\\\\m=4/0.2\\\\m=20g$

Now substitute in the general solution of the differential equation, to find A:

$m=Ae^{(0.2t)}\\\\20=Ae^{(0.2\times 3)}\\\\A=20/e^{(0.6)}\\\\A=10.976$

Round A to 1 significant figure:

A = 10.

Particular solution:

$m=10e^{(0.2t)}$

Question 4. What was the mass of the bacteria at time =0?

Substitute t = 0 in the equation of the particular solution:

$m=10e^{0}\\\\m=10g$

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2 years ago

Divide . Write the quotient as one power. The variable is not equal to zero.

gogolik [260]

I need the equation to be able to help

5 0

2 years ago

Directions: for questions 1 through 4, find the diagonal length of each solid figure.

Alex787 [66]

$\text{The length of the diagonal is }11.2\text{ mm}$

Here, we want to find the diagonal of the given solid

To do this, we need the appropriate triangle

Firstly, we need the diagonal of the base

To get this, we use Pythagoras' theorem for the base

The other measures are 6 mm and 8 mm

According ro Pythagoras' ; the square of the hypotenuse equals the sum of the squares of the two other sides

Let us have the diagonal as l

Mathematically;

$\begin{gathered} l^2=6^2+8^2 \\ l^2\text{ = 36 + 64} \\ l^2\text{ =100} \\ l\text{ = }\sqrt[]{100} \\ l\text{ = 10 mm} \end{gathered}$

Now, to get the diagonal, we use the triangle with height 5 mm and the base being the hypotenuse we calculated above

Thus, we calculate this using the Pytthagoras' theorem as follows;

$\begin{gathered} d^2=5^2+10^2 \\ d^2\text{ = 25 + 100} \\ d^2\text{ = 125} \\ d\text{ = }\sqrt[]{125} \\ d\text{ = }11.2\text{ mm} \end{gathered}$

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7 months ago

The area of a rectangular painting is 1/6 square yard. The width is 2/3 yard. What is the length of the painting use the formula

STatiana [176]

The length of the painting is 1/4.

According to the statement

we have to find the length of the rectangular painting with the help of the given information.

So, For this purpose, we know that the

The given information is:

The area of a rectangular painting is 1/6 square yard. The width is 2/3 yard.

And we have to use the formula

Area = Length * Breadth

So, Substitute the values in it then solve

So,

Area = Length * Breadth

1/6= Length * 2/3

1/6 = 2L/3

1 = 12L/3

1 = 4L

L = 1/4.

The value of the length is 1/4.

So, The length of the painting is 1/4.

Learn more about area of a rectangle here

brainly.com/question/2607596

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1 year ago