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uranmaximum [27]
2 years ago
15

Geometry and Modeling:

Mathematics
1 answer:
Ad libitum [116K]2 years ago
3 0
Honestly dont know i need help
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Is (x − 2) a factor of f(x) = x3 − 2x2 + 2x + 3? Explain your reasoning.
Drupady [299]

Answer:

❌

Step-by-step explanation:

If (x-a) is a factor of a polynomial then the polynomial must equal zero .

Here's what I mean :

x - 2 = 0  

x = 2

(2)³-2(2)²+2(2) + 3 = 0 ❌

8 - 8 +4 +3 = 0 ❌

7 = 0 ❌

Hope this helped and have a good day

6 0
2 years ago
If x = 3, calculate the value of: x3 - x
Sergeeva-Olga [200]
You have to fill in 3 for x so it woul look like 3x3-3 and that would be 6.
8 0
4 years ago
Read 2 more answers
Me. Mesa and Ms. Felipe are going to race each other to see who is going to pay for lunch. Ms. Felipe decides to give Ms. Messa
tia_tia [17]

Answer:

1. y=7x

2. y=9x

Step-by-step explanation:

7 0
3 years ago
Solve the following equation (If possible please show work)
natima [27]

Answer:

x = 1.8

Step-by-step explanation:

2 ( 4x-3) - 8 = 4-2x

Distribute

8x -6 -8 = 4- 2x

Combine like terms

8x - 14 = 4 - 2x

Add 2x to each side

8x - 14 +2x = 4-2x+2x

10x-14 = 4

Add 14 to each side

10x-14+14 = 4+14

10x = 18

Divide by 10

10x/10 = 18/10

x = 1.8

8 0
3 years ago
The rate at which rain accumulates in a bucket is modeled by the function r given by r(t)=10t−t^2, where r(t) is measured in mil
mars1129 [50]

Answer:

36 milliliters of rain.

Step-by-step explanation:

The rate at which rain accumluated in a bucket is given by the function:

r(t)=10t-t^2

Where r(t) is measured in milliliters per minute.

We want to find the total accumulation of rain from <em>t</em> = 0 to <em>t</em> = 3.

We can use the Net Change Theorem. So, we will integrate function <em>r</em> from <em>t</em> = 0 to <em>t</em> = 3:

\displaystyle \int_0^3r(t)\, dt

Substitute:

=\displaystyle \int_0^3 10t-t^2\, dt

Integrate:

\displaystyle =5t^2-\frac{1}{3}t^3\Big|_0^3

Evaluate:

\displaystyle =(5(3)^2-\frac{1}{3}(3)^3)-(5(0)^2-\frac{1}{3}(0)^3)=36\text{ milliliters}

36 milliliters of rain accumulated in the bucket from time <em>t</em> = 0 to <em>t</em> = 3.

4 0
3 years ago
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