I think its b because a coefficient is a number that is placed in front of a variable and the 4 is just a constant
Hello! Although I can't give you the answers automatically. I'll just show you some steps on how to subtract & if you're still not figuring it out just message me! :)
Step 1: You have to make sure both denominators are both exactly the same or you won't get the answer correctly.
Step 2: Then subtract the numerators
Step 3: Simplify if needed.
Ex; If I have 1/2 of the pizza and my friend has 1/6 of the pizza. What will be my result if I subtract the fractions?
We'll have to take 1/2 and 1/6. You'll have to find what makes those numbers, what I mean is by multiplying both numerators and denominators.

You multiply by 3.
2 x 3 = 6
Then you'll change the denominator into 1/2 = 1/6
Result:

Then you just subtract.
3 - 1 = 2
Hint: Denominator never changes when you have your final result. So it's 2/6. It needs to be simplified.

We divide by 2.
I hope this example helped you understand how to subtract fractions & if you don't know how to add mixed fractions you can always do around the world or other examples your teacher can provide! :)
Answer:
180
Step-by-step explanation:
The 12 th square number is
12² = 12 × 12 = 144
The 6 th square number is
6² = 6 × 6 = 36
Thus
sum = 144 + 36 = 180
Initially started 20 feet from the ground .
Went uphill 83 feet.
So: 20 + 83 = 103. The coaster is 103 ft above at this point.
Went down 42 feet
So: 103 - 42 = 61.
Went up 128 feet
So: 61 + 128 = 189
Finally, went down 90 feet
So: 189 - 90 = 99
99 ft above ground.
I assume you're needing to find
given those two functions you have.
![\begin{aligned}(f+g)(x) &= f(x) + g(x) \\[0.5em] &= (5x^3+5x^2-6x+3) + (x^3-4x^2+x-2)\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%28f%2Bg%29%28x%29%20%26%3D%20f%28x%29%20%2B%20g%28x%29%20%5C%5C%5B0.5em%5D%20%26%3D%20%285x%5E3%2B5x%5E2-6x%2B3%29%20%2B%20%28x%5E3-4x%5E2%2Bx-2%29%5Cend%7Baligned%7D)
From there, you combine like terms:
![\begin{aligned}(f+g)(x) &= f(x) + g(x) \\[0.5em] &= (5x^3+5x^2-6x+3) + (x^3-4x^2+x-2) \\[0.5em] &= 6x^3+x^2-5x+1\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%28f%2Bg%29%28x%29%20%26%3D%20f%28x%29%20%2B%20g%28x%29%20%5C%5C%5B0.5em%5D%20%26%3D%20%285x%5E3%2B5x%5E2-6x%2B3%29%20%2B%20%28x%5E3-4x%5E2%2Bx-2%29%20%5C%5C%5B0.5em%5D%20%26%3D%206x%5E3%2Bx%5E2-5x%2B1%5Cend%7Baligned%7D)