Answer:
Step-by-step explanation:
The relation is not a function when x -value is same but y- values are different.
#1
#2
- k^2 - 5k = k + 7
- k^2 - 6k = 7
- k^2 - 6k + 9 = 16
- k - 3 = 4 ⇒ k = 7
- k - 3 = -4 ⇒ k = -1
#3
- k^3 - 5k^2 + 3k = -k
- k^3 - 5k^2 + 4k = 0
- k(k^2 - 5k + 4) = 0
- k = 0, k = 1, k = 4
#4
- |k + 1| + 2 = 8
- |k + 1| = 6
- k = 5, k = -7
Answer:
222! thats your answer!
Step-by-step explanation:
You can solve for the velocity and position functions by integrating using the fundamental theorem of calculus:
<em>a(t)</em> = 40 ft/s²
<em>v(t)</em> = <em>v </em>(0) + ∫₀ᵗ <em>a(u)</em> d<em>u</em>
<em>v(t)</em> = -20 ft/s + ∫₀ᵗ (40 ft/s²) d<em>u</em>
<em>v(t)</em> = -20 ft/s + (40 ft/s²) <em>t</em>
<em />
<em>s(t)</em> = <em>s </em>(0) + ∫₀ᵗ <em>v(u)</em> d<em>u</em>
<em>s(t)</em> = 10 ft + ∫₀ᵗ (-20 ft/s + (40 ft/s²) <em>u</em> ) d<em>u</em>
<em>s(t)</em> = 10 ft + (-20 ft/s) <em>t</em> + 1/2 (40 ft/s²) <em>t</em> ²
<em>s(t)</em> = 10 ft - (20 ft/s) <em>t</em> + (20 ft/s²) <em>t</em> ²
400 : 1kg
400 : 1000
1 : 2.5
n = 2.5
