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brilliants [131]

3 years ago

10

Find an irrational number that is between 5.2 and 5.5

2 answers:

svlad2 [7]3 years ago

8 0

Answer is 5.3 I learned this last year in 8th grade

uysha [10]3 years ago

6 0

Answer:

answer is 5.3 cuz I am smart I learned this so I'm here to help

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which set does square 7 belong to? integers and irrational numbers irrational and real numbers real and rational numbers rationa

pashok25 [27]

Answer:This number belongs to a set of numbers that mathematicians call rational numbers. Rational numbers are numbers that can be written as a ratio of two integers. ... square root of a number that is not a perfect square, for example , is irrational. ... The set of real numbers is all the numbers that have a location on the number ...

Step-by-step explanation:

8 0

2 years ago

How do you solve x^2 plus 16x plus 63=0?

Alex

$x^2+ 16x + 63=0 \\ \\a=1, \ b=16 , \ c=63 \\ \\ \Delta =b^2-4ac =16^2 -4\cdot1\cdot 63 = 256 -252 = 4 \\ \\x_{1}=\frac{-b-\Delta }{2a}=\frac{-16-\sqrt{4}}{2 }=\frac{-16-2}{2}=-\frac{-18}{2}=-9 \\ \\x_{2}=\frac{-b+\Delta }{2a}=\frac{-16+\sqrt{4}}{2 }=\frac{-16+2}{2}=-\frac{-14}{2}=-7 \\ \\ \\Answer : \ x= -7 \ \ or \ \ x= -9$

8 0

3 years ago

Please help me with this I need to find out what y is

julsineya [31]

Answer:

26°

Step-by-step explanation:

<DFG+<EFG = 180°( Being sum of adjacent angle in linear pair is 180°)

You can also write;

<DFG+<EFG = 180°( Being sum of supplementary angle is 180°)

By putting the value of those angles;

5y+3+(2y-5)=180

5y+3+2y-5=180

5y+2y-5+3 =180°

7y-2=180°

7y=180+2

7y=182

y=182/7

y=26°

Hence,

The value of y is 26°

5 0

1 year ago

Please answer to receive ten points. I'll vote who answers first the brainliest if its correct.

beks73 [17]

The distance between points $P_1(x_1,y_1)$ and $P_2(x_2,y_2)$ can be calculated using formula

$P_1P_2=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}.$

1.

$AB=\sqrt{(-7-(-11))^2+(8-4)^2}=\sqrt{16+16}=\sqrt{32}=4\sqrt{2}\approx 5.657.$

2.

$AC=\sqrt{(-4-(-11))^2+(4-4)^2}=\sqrt{49+0}=\sqrt{49}=7.$

3.

$CB=\sqrt{(-7-(-4))^2+(8-4)^2}=\sqrt{9+16}=\sqrt{25}=5.$

Then

$P_{ABC}=5.657+7+5=17.657\approx 17.7$

Answer: correct choice is C.

3 0

2 years ago

Find all solutions to x³+3x² − 9x − 27 = 0 by factoring the equation.

SCORPION-xisa [38]

Answer:

The solutions are $x=-3,\:x=3$

Step-by-step explanation:

To factor this cubic polynomial $x^3+3x^2-9x-27$ you must:

Group the polynomial into two sections

$x^3+3x^2-9x-27=\left(x^3+3x^2\right)+\left(-9x-27\right)$

Factor out -9 from $(-9x-27)$

$(-9x-27)=-9\left(x+3\right)$

Factor out $x^2$ from $(x^3+3x^2)$

$(x^3+3x^2)=x^2\left(x+3\right)$

$x^3+3x^2-9x-27=-9\left(x+3\right)+x^2\left(x+3\right)$

Factor out common term $x+3$

$-9\left(x+3\right)+x^2\left(x+3\right)=\left(x+3\right)\left(x^2-9\right)$

$x^3+3x^2-9x-27=\left(x+3\right)\left(x^2-9\right)$

Factor $x^2-9$

$x^2-9=\left(x+3\right)\left(x-3\right)$

$x^3+3x^2-9x-27= \left(x+3\right)\left(x+3\right)\left(x-3\right)$

$x^3+3x^2-9x-27=\left(x+3\right)^2\left(x-3\right)=0$

Using the Zero Factor Theorem: = 0 if and only if = 0 or = 0

$x+3=0, \quad{x=-3}\\x-3=0, \quad{x=3}$

The solutions are

$x=-3,\:x=3$

3 0

2 years ago