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1 year ago

The post-world war ii record shows that recessionary gaps may be long-lasting because ____ tends not to occur

1 answer:

6 0

The post world war II record shows that recessionary gaps may be long-lasting because <u>deflation</u> tends not to occur.

Deflation is when customer and asset prices lower over time, and shopping power will increase. Essentially, you may buy greater goods or offerings the day after today with the identical amount of cash you've got nowadays. this is the replicate picture of inflation, that is the gradual growth in costs across the economy.

Deflation is when the charges of products and offerings decrease throughout the complete economic system, increasing the shopping power of clients. it is the opposite of inflation and may be taken into consideration as terrible for a state as it can signal a downturn in an economic system, leading to a recession or despair.

A recessionary gap, or contractionary gap, happens when a rustic's actual GDP is decreased than its GDP at complete employment. Recessionary gaps near when actual wages go back to equilibrium, and the number of exertions demanded equals the amount supplied

Learn more about deflation here brainly.com/question/13562161

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Q1. sin27° = x/8

Solution:

We have to solve for x, therefore, we will rearrange the given equation for x.

We get,
x = 8 × sin27°

Using the calculator,

sin27° = 0.45

Now substitute the value of sin27° into the main equation.

we get,
x = 8 × 0.45
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Q2. tan 18° = n / 75

Solution:
We have to solve for n, therefore, we will rearrange the given equation for n.
We get,
n = 75 × tan 18°
Using the calculator,
tan 18° = 0.32
Now substitute the value of tan 18° into the main equation.
we get,
x = 75 × 0.32
x = 24.37 (rounded to the nearest hundredth)

Q3. sin40° = 4 / a

Solution: We have to solve for a, therefore, we will rearrange the given equation for a.
We get,
a = 4 ÷ sin40°
Using the calculator,
sin40° = 0.64
Now substitute the value of sin40° into the main equation.
we get,
a = 4 ÷ 0.64
a = 6.25 (rounded to the nearest hundredth)

Q4. cos5° = 92 / y

Solution: We have to solve for y, therefore, we will rearrange the given equation for y.
We get,
y = 92 ÷ cos5°
Using the calculator,
Cos5° = 0.99
Now substitute the value of cos5° into the main equation.
we get,
y = 92 ÷ 0.99
y = 92.92 (rounded to the nearest hundredth)

Q5: Given the shape attached, therefore, using the triangle given, we have:
Angle of elevation = 35°
length of Opposite side to the angle = x
Length of Hypoteneus = 12
Calculations:
Using the SOH CAH TOA rules:
SOH stands for SineФ = Opposite ÷ Hypotenuse.

CAH stands for CosineФ = Adjacent ÷ Hypotenuse.

TOA stands for TangentФ = Opposite ÷ Adjacent.

Hence,

SineФ = Opposite ÷ Hypotenuse

Substituting the values:

Sine35° = x ÷ 12

0.5735 = x ÷ 12

x = 0.5735 × 12

x = 6.88 (rounded to the nearest hundredth)

Q6: Given the shape attached, therefore, using the triangle given, we have:

Angle of elevation = 54°
length of the adjacent side to the angle = x
Length of Hypoteneus = 30
Calculations:
Using the SOH CAH TOA rules:

Hence,

CosineФ = Adjacent ÷ Hypotenuse

Substituting the values:

Cos54° = x ÷ 30

0.5877 = x ÷ 30

x = 0.5877 × 30

x = 17.63 (rounded to the nearest hundredth)

Q7: Given the shape attached, therefore, using the triangle given, we have:

Angle of elevation = 22°
length of the adjacent side to the angle = 85
length of the opposite side to the angle = x
Calculations:

Using the SOH CAH TOA rules:

Hence,

TangentФ = Opposite ÷ Adjacent

Substituting the values:

tan22° = x ÷ 85

0.4040 = x ÷ 85

x = 0.4040 × 85

x = 34.34 (rounded to the nearest hundredth)

Q8: Given the shape attached, therefore, using the triangle given, we have:

Angle of elevation = 16°
length of the opposite side to the angle = x
Length of Hypoteneus = 14
Calculations:
Using the SOH CAH TOA rules:
Hence,

CosineФ = Adjacent ÷ Hypotenuse

Substituting the values:

Sine16° = x ÷ 14

0.2756 = x ÷ 14

x = 0.2756 × 14

x = 3.86 (rounded to the nearest hundredth)

Q9: Given the shape attached, therefore, using the triangle given, we have:

Angle of elevation = 65°
length of the adjacent side to the angle = 9
length of the opposite side to the angle = x
Calculations:
Using the SOH CAH TOA rules:
Hence,

TangentФ = Opposite ÷ Adjacent

Substituting the values:

tan65° = x ÷ 9

2.1445 = x ÷ 9

x = 2.1445 × 9

x = 19.30 (rounded to the nearest hundredth)

Q10: Given the shape attached, therefore, using the triangle given, we have:

Angle of elevation = 51°
length of the adjacent side to the angle = x
Length of Hypoteneus = 70
Calculations:
Using the SOH CAH TOA rules:
Hence,

CosineФ = Adjacent ÷ Hypotenuse

Substituting the values:

Cos51° = x ÷ 70

0.6293 = x ÷ 70

x = 0.6293 × 70

x = 44.05 (rounded to the nearest hundredth)

Q11: Given the shape attached, therefore, using the triangle given, we have:

Angle of elevation = 36°
length of the opposite side to the angle = 15
Length of Hypoteneus = x
Calculations:
Using the SOH CAH TOA rules:
Hence,

CosineФ = Adjacent ÷ Hypotenuse

Substituting the values:

Sine36° = 15 ÷ x

0.5877 = 15 ÷ x

x = 15 ÷ 0.5877

x = 25.52 (rounded to the nearest hundredth)

Q12: Given the shape attached, therefore, using the triangle given, we have:

Angle of elevation = 60°
length of the adjacent side to the angle = x
length of the opposite side to the angle = 100

Calculations:
Using the SOH CAH TOA rules:

Hence,

TangentФ = Opposite ÷ Adjacent

Substituting the values:

tan65° = 100 ÷ x

2.1445 = 100 ÷ x

x = 100 ÷ 2.1445

x = 46.63 (rounded to the nearest hundredth)

Q13: When a 25-ft ladder is leaned against a wall, it makes a 72° with the ground. How high up on wall does the ladder reach?

Solution: Given the shape attached, therefore, using the triangle given, we have:

The angle of elevation from the ground = 72°
length of the wall opposite to the angle = X
Length of ladder (Hypoteneus) = 25 feet

Calculations:
Using the SOH CAH TOA rules:
Hence,

SineФ = Opposite ÷ Hypotenuse

Substituting the values:

Sine72° = x ÷ 25

0.9510 = x ÷ 25

x = 25 ÷ 0.9510

x = 23.77 (rounded to the nearest hundredth)

ANSWERS TO QUESTION 14 AND 15 ARE ATTACHED

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3 years ago