Answer:
0.45 from mom and 0.05 from dad.
Explanation:
The recombinant progeny might occur due to the crossing over at the time of meiosis in which the exchange of chromosomes occur in the homologous chromosomes of non sister chromatids.
The progeny receives half of their chromosome from the mother and half from the father. The mother 50% AZ and 50% az chromosomes respectively. The 10% recombination has occured due to which the mother chromosomes is reduce upto 45%. The recombinant 10% will be aZ and Az and has 5% frequency. Mom has the ability of az chromosomes is 0.45 %. The father has the genotype 50% Az and 50% aZ. The 10% recombination has occured due to which the father chromosomes is reduce upto 45%. The recombinant will be az and AZ with 5% frequency. So, father has az with 0.05 % probability.
Thus, the answer is 0.45 from mom and 0.05 from dad.
Answer:
Yes
Explanation:
Range rule of thumb predicts the Range to be a multiple of 4 of the standard deviation or to be four times the standard deviation. Making the usual values equal to 2 standard deviations distanct of the mean of the data distribution.
In a given distribution with mean and standard deviation that is obtained, the usual values in mean (as seen in the attached image).
2*standard deviation and mean + 2*standard deviation.
If the data point is not up to the mean
- 2* standard deviation is taken to be significantly low.
If the data point is more than the mean
+ 2*standard deviation is taken to be significantly high.
Let's take the xbar to be the mean and s as standard deviaiton
Given,
mean, xbar = 1116.2
standard deviation, s =127.7
The range rule of thumb shows that the usual values are within 2 standard deviations from the mean
Lower boundary
= xbar - 2s
= 1116.2 - 2(127.7)
= 860.8
Upper boundary
= xbar + 2s
= 1116.2 + 2(127.7)
= 1371.6
We should note that 1411.6 is not between 860.8 and 1371.6, which connotes that 1411.6cm^3 is unusually high.
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