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podryga [215]
2 years ago
7

Wai Kit had $45 more than Cheryl and 0.25 of what Zheng Yi had. If they had $510 altogether, how much less money did Cheryl have

than Zheng Yi?
Mathematics
1 answer:
GenaCL600 [577]2 years ago
4 0

Step-by-step explanation:

Wai 1unit+45

Cheryl 1unit

Zheng 4units+180

Altogether 6units+225=510

6units = 510-225

6units=285

1unit=285÷6

= $47.5

So Wai =47.5+45 = 92.5

Cheryl =47.5

Zheng =4×47.5+180 =370

370-47.5=$322.5

Answer $322.5

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A triangle has an angle that measures 95°. The other two angles are in a ratio of 3:14. What are the measures of those two angle
Marta_Voda [28]

Answer: 15° and 70°

Step-by-step explanation:

The sum of angles of a triangle is 180.

One of the angle is given to be 95°, this means that the sum of the remaining two angles will be ;

180 - 95 =  85°

The ratio of the two sides is given to be 3 : 14

Calculating the angles of each ,the angle with the ratio 3 will be

3/17 x 85 = 15°

The angle with the ratio 14 will be

14/17 x 85 = 70°

Therefore : the measures of the two angles are : 15° and 70°

7 0
3 years ago
I need helppp what’s the answerrr?!!?
nevsk [136]

Answer:

3,240

Step-by-step explanation:

6 0
2 years ago
Número racional no entero
Varvara68 [4.7K]

An estar escrito en la forma n / 1. Por ejemplo, 5 = 5/1 y, por tanto, 5 es un número racional. Sin embargo, números como 1/2, 45454737/2424242 y -3/7 también son racionales, ya que son fracciones cuyo numerador y denominador son números enteros.

Espero que esto te ayude

6 0
2 years ago
Which function below BEST describes the height of the ball after the xth bounce?
otez555 [7]
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6 0
2 years ago
Use the Chain Rule to find the indicated partial derivatives. z = x^4 + xy^3, x = uv^4 + w^3, y = u + ve^w Find : ∂z/∂u , ∂z/∂v
k0ka [10]

I'll use subscript notation for brevity, i.e. \frac{\partial f}{\partial x}=f_x.

By the chain rule,

z_u=z_xx_u+z_yy_u

z_v=z_xx_v+z_yy_v

z_w=z_xx_w+z_yy_w

We have

z=x^4+xy^3\implies\begin{cases}z_x=4x^3+y^3\\z_y=3xy^2\end{cases}

and

\begin{cases}x=uv^4+w^3\\y=u+ve^w\end{cases}\implies\begin{cases}x_u=v^4\\x_v=4uv^3\\x_w=3w^2\\y_u=1\\y_v=e^w\\y_w=ve^w\end{cases}

When u=1,v=1,w=0, we have

\begin{cases}x(1,1,0)=1\\y(1,1,0)=2\end{cases}\implies\begin{cases}z_x(1,2)=12\\z_y(1,2)=12\end{cases}

and the partial derivatives take on values of

\begin{cases}x_u(1,1,0)=1\\x_v(1,1,0)=4\\x_w(1,1,0)=0\\y_u(1,1,0)=1\\y_v(1,1,0)=1\\y_w(1,1,0)=1\end{cases}

So we end up with

\boxed{\begin{cases}z_u(1,1,0)=24\\z_v(1,1,0)=60\\z_w(1,1,0)=12\end{cases}}

3 0
3 years ago
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