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2 years ago

Which line segments are parallel in the diagram?

Mathematics

2 answers:

storchak [24]2 years ago

8 0

The last option ,KH and LM

irakobra [83]2 years ago

7 0

Answer: C

Step-by-step explanation:

PQ is would be parallel,and because of the process of elimination,That would leave you with the answer being C.

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If two standard six-sided dice are tossed, what is the probability that a 5 is rolled on at least one of the two dice? express y

zaharov [31]

We define the probability of a particular event occurring as:
$\frac{number\ of \ desired\ outcomes}{number\ of\ possible\ outcomes}$

What are the total number of possible outcomes for the rolling of two dice? The rolls - though performed at the same time - are independent, which means one roll has no effect on the other. There are six possible outcomes for the first die, and for each of those, there are six possible outcomes for the second, for a total of 6 x 6 = 36 possible rolls.

Now that we've found the number of possible outcomes, we need to find the number of desired outcomes. What are our desired outcomes in this problem? They are asking for all outcomes where there is at least one 5 rolled. It turns out, there are only 3:

(1) D1 - 5, D2 - Anything else, (2), D1 - Anything else, D2 - 5, and (3) D1 - 5, D2 - 5

So, we have $\frac{3}{36} = \frac{1}{12}$ probability of rolling at least one 5.

6 0

2 years ago

How do you this question (pre-cal)

Novay_Z [31]

The goal to proving identities is to transform one side into the other. We can only pick one side to transform while the other side stays the same the entire time. The general rule of thumb is to transform the more complicated side (though there may be exceptions to this guideline).

So I'll take the left hand side and try to turn it into $\csc^2( B )$

One way we can do that is through the following steps:

$\frac{\tan(B) + \cot(B)}{\tan(B)} = \csc^2(B)\\\\\frac{\tan(B)}{\tan(B)} + \frac{\cot(B)}{\tan(B)} = \csc^2(B)\\\\1 + \cot(B)*\frac{1}{\tan(B)} = \csc^2(B)\\\\1 + \cot(B)*\cot(B) = \csc^2(B)\\\\1 + \cot^2(B) = \csc^2(B)\\\\1 + \frac{cos^2(B)}{\sin^2(B)} = \csc^2(B)\\\\\frac{sin^2(B)}{\sin^2(B)}+\frac{cos^2(B)}{\sin^2(B)} = \csc^2(B)\\\\\frac{sin^2(B)+cos^2(B)}{\sin^2(B)} = \csc^2(B)\\\\\frac{1}{\sin^2(B)} = \csc^2(B)\\\\\csc^2(B)=\csc^2(B) \ \ {\Large \checkmark}\\\\$

Since we've shown that the left hand side transforms into the right hand side, this verifies the equation is an identity.

4 0

2 years ago

A carpenter worked 10 weeks on a particular job, 51/2 days per week and 7 3/4 hours per day. How many hours did the carpenter wo

Luden [163]

Answer:

= 426 1/4 hr.

Step-by-step explanation:

5 1/2 = 5.5 Days in a week

7 3/4 = 7.75 hr. Per Day

Total hours in a week = 5.5 × 7.75 = 42.625 hr in a week

In 10 weeks = 42.625 × 10 = 426.25 hr.

5 0

2 years ago

What is the area of the square?

NISA [10]

The area is 4 square meters, because 2x2 would be 4

7 0

2 years ago

Type The missing number that makes these fractions equal: 4/?=2/8

natka813 [3]

Answer:

Step-by-step explanation:

2/8 is = to 1/4

4/16 is = to 1/4

GIVE ME BRAINLIESTTTTT

4 0

1 year ago