74=x+y is the equation at the beginning we will say that x is the smaller number and y is the larger one. Now we substitute the larger number (y) for 26+2x. Plug that into the beginning equation to get 74= x+ 26+2x. Now solve.
74=3x+26
48=3x
16=x
So we know that our smaller number is 16. To find the larger number we plug the value of the smaller number into the equation for the larger number like this.
y=26+2x
y=26+2(16)
y=26+32
y=58.
So to check our answer we can plug in both values into the beginning equation.
74=58+16
74=74.
So to sum this up the smaller number is 16 and the larger number is 58.
Answer:
I think it's 6x^2
Step-by-step explanation:
SOH CAH TOA tells you ...
... Tan(θ) = Opposite/Adjacent
You have ...
... Tan(θ) = (3)/(4)
Matching parts of the two expressions, we see ...
... Adjacent = (4)
_____
In the context of this problem we might reasonably assume that the adjacent side length is 4 units. In any other context, the best we might say is that it is 4/3 times the length of the opposite side.
