Subtract 5 to both sides so that the equation becomes -2x^2 + 6x - 1 = 0. To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0 x = [ -b ± √(b^2 - 4ac) ] / (2a) x = [ -6 ± √((6)^2 - 4(-2)(-1)) ] / ( 2(-2) ) x = [-6 ± √(36 - (8) ) ] / ( -4 ) x = [-6 ± √(28) ] / (-4) x = [-6 ± 2*sqrt(7) ] / (-4 ) x =3/2 ± -sqrt(7)/ 2 The answers are 3/2 + sqrt(7)/2 and 3/2 - sqrt(7)/2.
Let one acute angle be X and one be Y X+Y=90 -------Eq.1 2X+12=Y 2X-Y=-12------Eq.2 solving eq 1&2 we get, 3x=78 ∴X=26 substituting value X in equation.1 X+Y=90 Y=90-26 ∴Y=64 ⇒answer:- X=26° Y=64°
