Sierra buys lunch in the cafeteria everyday. Lunch costs $2.00 each day, how much did she spend after 5 days.

Find the missing term! if y=1+i, then y^3-3y^2+(-3y,-3y+1,3y,3i)-1=-i

Kazeer [188]

Y = 1 + i

(1 + i)^3 - 3 * (1 + i)^2 + k - 1 = -i 
(1 + 3i + 3i^2 + i^3) - 3 * (1 + 2i + i^2) + k - 1 = -i 
1 + 3i - 3 - i - 3 - 6i + 3 + k - 1 = -i 
1 - 3 - 3 + 3 - 1 + 3i - i - 6i + k = -i 
-3 - 4i + k = -i 
k = 4i - i + 3 
k = 3i + 3 
k = 3 * (1 + i) 
k = 3y

4 0

2 years ago

Johanna wrote the system of equations. 4 x - 3 y = 1, 5 x + 4 y = 9. If the second equation is multiplied by 4, what should the

polet [3.4K]

Answer:

The first equation must be multiplied by -5 to eliminate x variable by addition

Step-by-step explanation:

4 x - 3 y = 1 (1)

5 x + 4 y = 9 (2)

If the second equation is multiplied by 4

5x+4y=9. ×4

We have,

20x+16y=36 (3)

The first equation should be multiplied by -5 to eliminate x variable by addition

4x-3y=1 × -5

We have

-20x+15y=-5 (4)

Add equation (3) and (4) to eliminate x variable

20x+16y=36

-20x+15y=-5

31y=31

Divide both sides by 31

y=1

Substitute y=1 into equation (1)

4 x - 3 y = 1

4x-3(1)=1

4x-3=1

4x=1+3

4x=4

Divide both sides by 4

x=1

4 0

3 years ago

Read 2 more answers

A consulting firm has received 2 Super Bowl playoff tickets from one of its clients. To be fair, the firm is randomly selecting

Soloha48 [4]

Answer:

Therefore the only statement that is not true is b.)

Step-by-step explanation:

There employees are 6 secretaries, 5 consultants and 4 partners in the firm.

a.) The probability that a secretary wins in the first draw

= $\frac{number \hspace{0.1cm} of \hspace{0.1cm} secreataries}{total \hspace{0.1cm} number \hspace{0.1cm} of \hspace{0.1cm} employees} = \frac{6}{15}$

b.) The probability that a secretary wins a ticket on second draw. It has been given that a ticket was won on the first draw by a consultant.

p(secretary wins on second draw | consultant wins on first draw)

= $\frac{p((consultant \hspace{0.1cm} wins \hspace{0.1cm} on \hspace{0.1cm} first \hspace{0.1cm}draw)\cap( secretary\hspace{0.1cm} wins\hspace{0.1cm} on second \hspace{0.1cm}draw))}{p(consultant \hspace{0.1cm} wins \hspace{0.1cm} on \hspace{0.1cm} first \hspace{0.1cm}draw)}$

= $\frac{\frac{5}{15} \times \frac{6}{14}}{\frac{5}{15} } = \frac{6}{14}$ .

The probability that a ticket was won on the first draw by a consultant a secretary wins a ticket on second draw = $\frac{6}{15}$ is not true.

The probability that a secretary wins on the second draw = $\frac{number \hspace{0.1cm} of \hspace{0.1cm} secretaries \hspace{0.1cm} remaining } { number \hspace{0.1cm} of \hspace{0.1cm} employees \hspace{0.1cm} remaining} = \frac{6 - 1}{15 - 1} = \frac{5}{14}$

c.) The probability that a consultant wins on the first draw =

$\frac{number \hspace{0.1cm} of \hspace{0.1cm} consultants \hspace{0.1cm} } { number \hspace{0.1cm} of \hspace{0.1cm} employees \hspace{0.1cm} } = \frac{5 }{15} = \frac{1}{3}$

d.) The probability of two secretaries winning both tickets

= (probability of a secretary winning in the first draw) × (The probability that a secretary wins on the second draw)

= $\frac{6}{15} \times \frac{5}{14} = \frac{1}{7}$

Therefore the only statement that is not true is b.)

5 0

3 years ago

Solve the equation for the given variable. * 3(x - 5) = 7

MariettaO [177]

Answer:

x = 7.33

Step-by-step explanation:

3x - 15 = 7

3x = 7 + 15

3x = 22

x = 7.33

4 0

3 years ago

Nancy and Kevin collect coins. Nancy has x coins. Kevin has 9 coins fewer than five times the number of coins Nancy has. Write a

Alexus [3.1K]

Answer:

x + (5x-9)

Step-by-step explanation:

x stands for the number of coins Nancy has

Kevin has 9 less than 5 times what Nancy has, so his part of the expression is 5x-9

To find the total number of coins they have, you have to add Nancy's number of coins x plus Kevin's number of coins 5x-9

x + (5x-9)

But you have to put parentheses around Kevin's 5x-9 so that part of the expression is calculated first, as per order of operations

3 0

2 years ago