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RSB [31]
3 years ago
13

What is the measure of DEF

Mathematics
2 answers:
Daniel [21]3 years ago
8 0

<em>Answer:</em>

<em>1</em><em>0</em><em>5</em><em>°</em>

<em>Solution</em><em>,</em>

<em>let \:  < def \: be \: x \\ x  + 28 + 47 = 180 \\ or \: x + 75 = 180 \\ or \: x = 180 - 75 \\ x = 105 \\ hope \: it \: helps \\ good \: luck \: on \: your \: assignment</em>

den301095 [7]3 years ago
4 0

The total angle of a triangle is 180°. Using this we can find the angle DEF(x).

180=28+47+x

180=75+x

180-75=x

105=x

SO angle DEF=105°

Hope it helps!!

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Brian and Christina started keeping track of their workouts. Brian did 85 sit-ups the first week and 90 sit-ups each week after
IrinaK [193]

Brian-90×5+85=535

Christina-90×5+65=515

So after 5 weeks Brian will do 535 push ups and Christina will have done 515.

6 0
3 years ago
HELPPP!!!!!!!!!!!!!!!!! What’s the slope of line. (-6,19) (8,19)
soldi70 [24.7K]

Answer: m=o

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
77+ 2(3x – 5) = 8 – 3(2x + 1)<br> 78 2 + 3(2 -7) – 0 - 13 I 1).
nika2105 [10]

Answer:

-31/6

Step-by-step explanation:

77+2(3x-5)=8-3(2x+1)

77+6x-10=8-6x-3

77-10+6x=8-3-6x

67+6x=5-6x

67+6x-(-6x)=5

67+6x+6x=5

67+12x=5

12x=5-67

12x=-62

x=-62/12

simplify

x=-31/6

3 0
3 years ago
Find the balance on a deposit of $455 that earns 4% interest compounded annually for 2 years. $36.40 $491.40 $492.13 $819
STatiana [176]
A=P(1+ \frac{r}{n})^{tn}
A=future amount
P=present amount
r=rate in decimal
n=number of times per year compounded
t=time in years

given
P=455
r=4%=0.04
n=1
t=2

A=455(1+ \frac{0.04}{1})^{(2)(1)}
A=455(1+ 0.04)^{2}
A=455(1.04)^{2}
A=492.128
round
$492.13
3rd option
5 0
3 years ago
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PLEASE HELP WITH GRADE 11 MATH. Make sure you show the formula. Substitute values and show all mathematicall operations! show yo
Degger [83]

3x+y

x

​

 

=−3

=−y+3

​

The second equation is solved for xxx, so we can substitute the expression -y+3−y+3minus, y, plus, 3 in for xxx in the first equation:

\begin{aligned} 3\blueD{x}+y &= -3\\\\ 3(\blueD{-y+3})+y&=-3\\\\ -3y+9+y&=-3\\\\ -2y&=-12\\\\ y&=6 \end{aligned}

3x+y

3(−y+3)+y

−3y+9+y

−2y

y

​

 

=−3

=−3

=−3

=−12

=6

​

Plugging this value back into one of our original equations, say x = -y +3x=−y+3x, equals, minus, y, plus, 3, we solve for the other variable:

\begin{aligned} x &= -\blueD{y} +3\\\\ x&=-(\blueD{6})+3\\\\ x&=-3 \end{aligned}

x

x

x

​

 

=−y+3

=−(6)+3

=−3

​

The solution to the system of equations is x=-3x=−3x, equals, minus, 3, y=6y=6y, equals, 6.

We can check our work by plugging these numbers back into the original equations. Let's try 3x+y = -33x+y=−33, x, plus, y, equals, minus, 3.

\begin{aligned} 3x+y &= -3\\\\ 3(-3)+6&\stackrel ?=-3\\\\ -9+6&\stackrel ?=-3\\\\ -3&=-3 \end{aligned}

3x+y

3(−3)+6

−9+6

−3

​

 

=−3

=

?

−3

=

?

−3

=−3

​

Yes, our solution checks out.

Example 2

We're asked to solve this system of equations:

\begin{aligned} 7x+10y &= 36\\\\ -2x+y&=9 \end{aligned}

7x+10y

−2x+y

​

 

=36

=9

​

In order to use the substitution method, we'll need to solve for either xxx or yyy in one of the equations. Let's solve for yyy in the second equation:

\begin{aligned} -2x+y&=9 \\\\ y&=2x+9 \end{aligned}

−2x+y

y

​

 

=9

=2x+9

​

Now we can substitute the expression 2x+92x+92, x, plus, 9 in for yyy in the first equation of our system:

\begin{aligned} 7x+10\blueD{y} &= 36\\\\ 7x+10\blueD{(2x+9)}&=36\\\\ 7x+20x+90&=36\\\\ 27x+90&=36\\\\ 3x+10&=4\\\\ 3x&=-6\\\\ x&=-2 \end{aligned}

7x+10y

7x+10(2x+9)

7x+20x+90

27x+90

3x+10

3x

x

​

 

=36

=36

=36

=36

=4

=−6

=−2

​

Plugging this value back into one of our original equations, say y=2x+9y=2x+9y, equals, 2, x, plus, 9, we solve for the other variable:

\begin{aligned} y&=2\blueD{x}+9\\\\ y&=2\blueD{(-2)}+9\\\\ y&=-4+9 \\\\ y&=5 \end{aligned}

y

y

y

y

​

 

=2x+9

=2(−2)+9

=−4+9

=5

​

The solution to the system of equations is x=-2x=−2x, equals, minus, 2, y=5y=5y, equals, 5.

5 0
2 years ago
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