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maw [93]
1 year ago
11

Simplify 10 times the square root of quantity 3 x end quantity plus 4 times the square root of quantity 3 x end quantity plus 5

times the square root of quantity 3 x end quantity. 9 times the square root of quantity 3 x end quantity 9 times the square root of quantity 6 x end quantity 19 times the square root of quantity 3 x end quantity 19 times the square root of quantity 9 x cubed
Mathematics
2 answers:
gladu [14]1 year ago
3 0

\\ \rm\dashrightarrow10\sqrt{3x}+4\sqrt{3x}+5\sqrt{3x}+9\sqrt{3x}+9\sqrt{6x}+19\sqrt{3x}+19\sqrt{9x^3}

\\ \rm\dashrightarrow (10+4+5+9+19)\sqrt{3x}+9\sqrt{6x}+19\sqrt{3^2x^2x}

\\ \rm\dashrightarrow 47\sqrt{3x}+9\sqrt{2x}\sqrt{3x}+57x\sqrt{x}

\\ \rm\dashrightarrow (47+9\sqrt{2x})\sqrt{3x}+57x\sqrt{x}

Aloiza [94]1 year ago
3 0

Answer:

19\sqrt{3x}

Step-by-step explanation:

Given expression:

10 \sqrt{3x}+4\sqrt{3x}+5\sqrt{3x}

Given answer options:

  • 9\sqrt{3x}
  • 9\sqrt{6x}
  • 19\sqrt{3x}
  • 19\sqrt{9x^3}

To simplify the given expression, factor out \sqrt{3x}:

\implies 10 \sqrt{3x}+4\sqrt{3x}+5\sqrt{3x}

\implies \sqrt{3x}(10+4+5)

Add the numbers in the parentheses:

\implies \sqrt{3x}(19)

Rearrange to standard form:

\implies 19\sqrt{3x}

Therefore, the answer is the third option.

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Let

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