Please help me solve 5x-2=1

The yield of a certain chemical reaction is believed to be related to temperature. A study collected the yield from 15 such reac

Nookie1986 [14]

Answer:

t = 0.05 / 0.017

Step-by-step explanation:

Given the table :

Variable ____ Estimate

Intercept 1 ____ 15.5 ____2.96

Temp 1 _______0.05 ___ 0.017

R-sq = 0.73

The test statistic for a regression test :

t = b1 / E

Where ;

b1 = slope ; E = Standard error of the slope

From the result table ;

b1 = 0.05 ;

E = 0.017

The test statistic, t = 0.05 / 0.017

5 0

3 years ago

1. 20-3 + 12 + 6 x 2

chubhunter [2.5K]

1. 41
2. 50
3. 10
4. 75
5. i’m not really sure

6 0

3 years ago

Taxes are what the government levies upon us to obtain the money needed tooperate true or false

Zina [86]

True. Is the answer because how else will the goverment get money for their tooperate.

8 0

3 years ago

Read 2 more answers

Hey guys, I need help with this word problem. I don't just want the answer. I would like the steps please!

ASHA 777 [7]

So, you take the equation for y given, y=0.28x+5.92. Then you substitute the values for x in, like so:
y=0.28(2)+5.92=6.42
y=0.28(5)+5.92=7.17
y=0.28(8)+5.92=7.92
So There's your table. Next:
7.88=0.28x+5.92
x=7, so the year when admission was approximately $7.88 is year 7.
Next,
10.04=0.28x+5.92
x=14.7142857143, which rounds to year 15.
I hope this helps!

7 0

3 years ago

Consider the following. (See attachment)

Furkat [3]

Answer:

Area: 16

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Calculus

Derivatives

Derivative Notation

Integrals - Area under the curve

Trig Integration

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Integration Property [Addition/Subtraction]: $\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx$

U-Substitution

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = 8sin(x) + sin(8x)$

$\displaystyle y = 0$

Bounds of Integration: 0 ≤ x ≤ π

Step 2: Find Area Pt. 1

Set up integral: $\displaystyle A = \int\limits^{\pi}_0 {[8sin(x) + sin(8x)]} \, dx$
Rewrite integral [Integration Property - Addition/Subtraction]: $\displaystyle A = \int\limits^{\pi}_0 {8sin(x)} \, dx + \int\limits^{\pi}_0 {sin(8x)} \, dx$
[1st Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle A = 8\int\limits^{\pi}_0 {sin(x)} \, dx + \int\limits^{\pi}_0 {sin(8x)} \, dx$
[1st Integral] Integrate [Trig Integration]: $\displaystyle A = 8[-cos(x)] \bigg| \limits^{\pi}_0 + \int\limits^{\pi}_0 {sin(8x)} \, dx$
[1st Integral] Evaluate [Integration Rule - FTC 1]: $\displaystyle A = 8(2) + \int\limits^{\pi}_0 {sin(8x)} \, dx$
Multiply: $\displaystyle A = 16 + \int\limits^{\pi}_0 {sin(8x)} \, dx$

Step 3: Identify Variables

Identify variables for u-substitution.

u = 8x

du = 8dx

Step 4: Find Area Pt. 2

[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle A = 16 + \frac{1}{8}\int\limits^{\pi}_0 {8sin(8x)} \, dx$
[Integral] U-Substitution: $\displaystyle A = 16 + \frac{1}{8}\int\limits^{8\pi}_0 {sin(u)} \, du$
[Integral] Integrate [Trig Integration]: $\displaystyle A = 16 + \frac{1}{8}[-cos(u)] \bigg| \limits^{8\pi}_0$
[Integral] Evaluate [Integration Rule - FTC 1]: $\displaystyle A = 16 + \frac{1}{8}(0)$
Simplify: $\displaystyle A = 16$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Integration - Area under the curve

Book: College Calculus 10e

4 0

3 years ago