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RUDIKE [14]
4 years ago
11

Order each model from greatest to least 5/6 7/8 2/3

Mathematics
1 answer:
Jlenok [28]4 years ago
8 0
2,3,5,6,7,8 IM sorry if its not the answer u were asking for 
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A bakery offers a sale price of $3.25 for 3 muffins. What is the price per dozen?
klio [65]

It is given that price of 3 muffins = $3.25

So price of 1 muffin=

\frac{3.25}{3}

And cost of 12 muffins

\frac{3.25}{3} *12 = $13

Therefore cost per dozen of muffins is $13 .

8 0
3 years ago
1) it takes 4 gallon jugs of water to fill
Ipatiy [6.2K]
The answer to your question is 13
5 0
3 years ago
–0.4(3x – 2) + StartFraction 2 x plus 4 Over 3 EndFraction for x = 4
Nadusha1986 [10]

Answer:

0

Step-by-step explanation:

Given

- 0.4(3x - 2) + \frac{2x+4}{3} ← substitute x = 4 into the expression

= - 0.4(3(4) - 2) + \frac{2(4)+4}{3}

= - 0.4(12 - 2) + \frac{8+4}{3}

= - 0.4(10) + \frac{12}{3}

= - 4 + 4 = 0

4 0
3 years ago
Read 2 more answers
The vertex angle of an isosceles triangle measures 42°. A base angle in the triangle has a measure given by
Dmitry_Shevchenko [17]

Answer:

x=33

Each base angle measures 69 degrees

Step-by-step explanation:

the 2  base angles are equal so  the measure of 1 base angle = (180 - 42) / 2

=  69 degrees

2x + 3 = 69

2x = 66

x = 33

5 0
3 years ago
An article describes an experiment to determine the effectiveness of mushroom compost in removing petroleum contaminants from so
alexgriva [62]

Solution :

Let p_1 and p_2  represents the proportions of the seeds which germinate among the seeds planted in the soil containing 3\% and 5\% mushroom compost by weight respectively.

To test the null hypothesis H_0: p_1=p_2 against the alternate hypothesis  H_1:p_1 \neq p_2 .

Let \hat p_1, \hat p_2 denotes the respective sample proportions and the n_1, n_2 represents the sample size respectively.

$\hat p_1 = \frac{74}{155} = 0.477419

n_1=155

$p_2=\frac{86}{155}=0.554839

n_2=155

The test statistic can be written as :

$z=\frac{(\hat p_1 - \hat p_2)}{\sqrt{\frac{\hat p_1 \times (1-\hat p_1)}{n_1}} + \frac{\hat p_2 \times (1-\hat p_2)}{n_2}}}

which under H_0  follows the standard normal distribution.

We reject H_0 at 0.05 level of significance, if the P-value or if |z_{obs}|>Z_{0.025}

Now, the value of the test statistics = -1.368928

The critical value = \pm 1.959964

P-value = $P(|z|> z_{obs})= 2 \times P(z< -1.367928)$

                                     $=2 \times 0.085667$

                                     = 0.171335

Since the p-value > 0.05 and $|z_{obs}| \ngtr z_{critical} = 1.959964$, so we fail to reject H_0 at 0.05 level of significance.

Hence we conclude that the two population proportion are not significantly different.

Conclusion :

There is not sufficient evidence to conclude that the \text{proportion} of the seeds that \text{germinate differs} with the percent of the \text{mushroom compost} in the soil.

8 0
3 years ago
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