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Igoryamba
2 years ago
6

Use the drop-down menus to complete the statements. in order for f–1(x) to be a function, the domain of f(x) can be restricted t

o . under this restriction, the domain of f–1(x) would be , having the same minimum value as the .
Mathematics
1 answer:
zmey [24]2 years ago
6 0

Using concepts of the inverse function, it is found that:

The domain of f(x) has to be restricted to x >= 1. Under this restriction, the domain of f-1(x), would be (2,∞), having the same minimum value as the original function f(x).

<h3>How to find the inverse of an equation or a function?</h3>

To find the inverse, we have to exchange x and y and then isolate y. This can only happen if the function f(x) is injective, that is, each value of the output is related to only one value of the input. Then:

  • The domain of f(x) is the range of the inverse function f-1(x).
  • The range of f(x) is the domain of the inverse function f-1(x).

Researching this problem on the internet, we are given an absolute value function with vertex at x = 1, meaning that for the inverse, the domain of f(x) has to be restricted to x >= 1. The domain of the inverse would be the range of f(x), which is (2,∞).

Then:

The domain of f(x) has to be restricted to x >= 1. Under this restriction, the domain of f-1(x), would be (2,∞), having the same minimum value as the original function f(x).

More can be learned about inverse functions at brainly.com/question/8824268

#SPJ1

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Answer:

C. (-13, -7)

Step-by-step explanation:

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x=\frac{m}{m+n} (x_2-x_1)+x_1\\\\y=\frac{m}{m+n} (y_2-y_1)+y_1

Therefore the coordinates of point X That divides line segment from Y(-8, 8) to T(-15, -13) in the ratio 5:2 is:

x=\frac{5}{5+2} (-15-(-8))+(-8)\\\\x=\frac{5}{7} (-15+8)-8=\frac{5}{7}(-7)-8=-5-8=-13 \\\\\\y=\frac{5}{5+2} (-13-8)+8\\\\y=\frac{5}{7} (-21)+8=5(-3)+8=-15+8=-7

Therefore the coordinates of point X is at (-13, -7)

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