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scoray [572]
3 years ago
12

Simplify 3(x+2)-6+x please!

Mathematics
2 answers:
kirill115 [55]3 years ago
7 0
The answer is 4x that the answer
andrew-mc [135]3 years ago
7 0

Answer:

4x

Step-by-step explanation:

use the distributive property

3(x+2) = 3x+6

3x+6-6+x

the 6 and -6 cancel out - equaling 0

3x+0+x

3x+x= 4x

4x+0 is the same as 4x.

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Joyce rented a booth at a carnival at a cost of $95 to sell handmade beaded necklaces. The cost of making and packaging each bea
xz_007 [3.2K]

Answer:

To make a profit of at least $500 she must sell at least 12 necklaces

Step-by-step explanation:

Joyce rented a booth at a carnival at a cost of $95 to sell handmade beaded necklaces. The cost of making and packaging each beaded necklace was $15. If Joyce sells the beaded necklaces at $35 each then we have to find beaded necklaces she sell to make a profit of at least $500.

The costs side of the equation, we have:

Let no. of necklaces that she sell are x

∴ The cost of making and packaging x beaded necklace is $15x

Total Cost = 95+15x

Now, Joyce sells the beaded necklaces at $35 each. Therefore, selling price will be $35x

To make a profit of at least $500 the equation can be written as

95+15x+500\leq35x

595\leq50x

⇒ x\geq11.9=12

Hence,  to make a profit of at least $500 she must sell at least 12 necklaces



7 0
3 years ago
Read 2 more answers
Use the sequence {−1,171,875;−234,375;−46,875;−9375,…} to answer the question.
vlabodo [156]

Answer: C

 

Step-by-step explanation:

the normal distribution is symmetric about its mean.  

so answer c) must be true.

6 0
3 years ago
You need at least $635 to go on a trip to Washington, DC. You already have $75 saved for the trip. You decide to save an additio
Reika [66]

Answer: $75 + $65w ≥ $635

Step-by-step explanation:

$635 is your goal and how much money you should earn

$75 is your already saved money

$65 is how much you're going to save every week

Ask yourself, how many weeks do you have to save money before you reach your goal of $635. Since we don't know this value, it's a variable, w.

4 0
3 years ago
Would like to know how to do this problem.
bogdanovich [222]

well it would be very helpful thank you

8 0
2 years ago
Suppose a, b denotes of the quadratic polynomial x² + 20x - 2022 & c, d are roots of x² - 20x + 2022 then the value of ac(a
Alja [10]
<h3><u>Correct Question :- </u></h3>

\sf\:a,b \: are \: the \: roots \: of \:  {x}^{2} + 20x - 2020 = 0 \: and \:  \\  \sf \: c,d \: are \: the \: roots \: of \:  {x}^{2}  -  20x  + 2020 = 0 \: then \:

\sf \: ac(a - c) + ad(a - d) + bc(b - c) + bd(b - d) =

(a) 0

(b) 8000

(c) 8080

(d) 16000

\large\underline{\sf{Solution-}}

Given that

\red{\rm :\longmapsto\:a,b \: are \: the \: roots \: of \:  {x}^{2} + 20x - 2020 = 0}

We know

\boxed{\red{\sf Product\ of\ the\ zeroes=\frac{Constant}{coefficient\ of\ x^{2}}}}

\rm \implies\:ab = \dfrac{ - 2020}{1}  =  - 2020

And

\boxed{\red{\sf Sum\ of\ the\ zeroes=\frac{-coefficient\ of\ x}{coefficient\ of\ x^{2}}}}

\rm \implies\:a + b = -  \dfrac{20}{1}  =  - 20

Also, given that

\red{\rm :\longmapsto\:c,d \: are \: the \: roots \: of \:  {x}^{2}  -  20x  + 2020 = 0}

\rm \implies\:c + d = -  \dfrac{( - 20)}{1}  =  20

and

\rm \implies\:cd = \dfrac{2020}{1}  = 2020

Now, Consider

\sf \: ac(a - c) + ad(a - d) + bc(b - c) + bd(b - d)

\sf \:  =  {ca}^{2} -  {ac}^{2} +  {da}^{2} -  {ad}^{2} +  {cb}^{2} -  {bc}^{2} +  {db}^{2} -  {bd}^{2}

\sf \:  =  {a}^{2}(c + d) +  {b}^{2}(c + d) -  {c}^{2}(a + b) -  {d}^{2}(a + b)

\sf \:  = (c + d)( {a}^{2} +  {b}^{2}) - (a + b)( {c}^{2} +  {d}^{2})

\sf \:  = 20( {a}^{2} +  {b}^{2}) + 20( {c}^{2} +  {d}^{2})

\sf \:  = 20\bigg[ {a}^{2} +  {b}^{2} + {c}^{2} +  {d}^{2}\bigg]

We know,

\boxed{\tt{  { \alpha }^{2}  +  { \beta }^{2}  =  {( \alpha   + \beta) }^{2}  - 2 \alpha  \beta  \: }}

So, using this, we get

\sf \:  = 20\bigg[ {(a + b)}^{2} - 2ab +  {(c + d)}^{2} - 2cd\bigg]

\sf \:  = 20\bigg[ {( - 20)}^{2} +  2(2020) +  {(20)}^{2} - 2(2020)\bigg]

\sf \:  = 20\bigg[ 400 + 400\bigg]

\sf \:  = 20\bigg[ 800\bigg]

\sf \:  = 16000

Hence,

\boxed{\tt{ \sf \: ac(a - c) + ad(a - d) + bc(b - c) + bd(b - d) = 16000}}

<em>So, option (d) is correct.</em>

4 0
2 years ago
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