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puteri [66]
2 years ago
6

What is the distance from (-3,8) and (13,-6)?

Mathematics
2 answers:
11111nata11111 [884]2 years ago
7 0

Answer:

d ≈ 21.26 units

Step-by-step explanation:

calculate the distance d using the distance formula

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = (- 3, 8 ) and (x₂, y₂ ) = (13 - 6 )

d = \sqrt{13-(-3))^2+(-6-8)^2}

   = \sqrt{(13+3)^2+(-14)^2}

   = \sqrt{16^2+196}

   = \sqrt{256+196}

   = \sqrt{452}

   ≈ 21.26 units ( to 2 dec. places )

Katarina [22]2 years ago
7 0

Answer:

The distance is 21.3

Step-by-step explanation:

The solution is in the attached image

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L=Length of the rectangular patio

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W=Width of the rectangular patio

f=foot

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L=25/2f

A=(103+1/8)f²=(824/8+1/8)f²=825/8f²

-----------------------------

Now, A=L*W=825/8f²

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<em>USE BODMAS</em>

Therefore:

25/2fW=825/8f²

So...

W=(825/8f²)/(25/2f)

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3 years ago
Two points (-2,4) and (2,4) and plotted on a coordinate grid. Which expression below can you use to find the distance between tw
Allushta [10]

Answer:

First, let's address the general case.

When we have two points (a,b) and (c,d)

The distance between those points can be written as:

D = √( (a - c)^2 + (b - d)^2)

In this case, the points are:

(-2,4) and (2,4)

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D = √( (-2 - 2)^2 + (4 - 4)^2) = √(-4)^2 = 4.

The equivalent expression to this is: |-2| + |2|

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3 years ago
in 1940, the u.s. army reported a total of 17,563 commissioned officers. of these, 939 were females. find the percent of female
Kisachek [45]

Answer: The percent of female commissioned officers in the army in 1940= 5.3%

Step-by-step explanation:

We are given that ,

The number of commissioned officers reported by U.S. Army  in 1940 = 17,563

The  number of female commissioned officers = 939

Then , the number of female commissioned officers in the army in 1940  would be :-

\dfrac{\text{\text{Number of Female officers}}}{\text{Total commissioned officers }}\times100

=\dfrac{939}{17563}\times100=5.3464670\approx5.3\%

Hence, the percent of female commissioned officers in the army in 1940= 5.3%

3 0
3 years ago
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