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3 years ago

Show all work to identify the asymptotes and zero of the faction f(x) = 4x/x^2 - 16.

Mathematics

1 answer:

Reptile [31]3 years ago

5 0

Answer:

asymptotes: x = -4, x = 4
zeros: x = 0

Step-by-step explanation:

The vertical asymptotes of the rational expression are the places where the denominator is zero:

x^2 -16 = 0

(x -4)(x +4) = 0 . . . . . true for x=4, x=-4

x = 4, x = -4 are the equations of the vertical asymptotes

The zeros of a rational expression are the places where the numerator is zero:

4x = 0

x = 0 . . . . . . divide by 4

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x = (u - v)/2

y = (u + v)/2

in which case the Jacobian and its determinant are

$J=\begin{bmatrix}x_u&x_v\\y_u&y_v\end{bmatrix}=\dfrac12\begin{bmatrix}1&-1\\1&1\end{bmatrix}\implies|\det J|=\left|\dfrac12\right|=\dfrac12$

The trapezoid R has two of its edges on the lines x + y = 8 and x + y = 9, so right away, we have 8 ≤ u ≤ 9.

Then for v, we observe that when x = 0 (the lowest edge of R), v = y ; similarly, when y = 0 (the leftmost edge of R), v = -x. So

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-u + v ≤ 2v ≤ u + v

-u ≤ v ≤ u

So, the integral becomes

$\displaystyle\iint_R5\cos\left(7\frac{y-x}{y+x}\right)\,\mathrm dA=\int_8^9\int_{-u}^u\frac52\cos\left(\frac{7v}u\right)\,\mathrm dv\,\mathrm du$

$=\displaystyle\frac52\int_8^9\frac u7(\sin7-\sin(-7))\,\mathrm du$

$=\displaystyle\frac57\sin7\int_8^9u\,\mathrm du$

$=\displaystyle\frac5{14}\sin7(9^2-8^2)=\boxed{\frac{85}{14}\sin7}$

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Which of these functions has an inverse function? Select all that apply.

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Anaika has found 25 coins this week, all quarters and dimes . If total worth of all coins is $4.00, how many of each coin does a

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